Angle 2 is 60. Find angle 8. Options: 140 100 40 60

One measure of general health is your body mass index (BMI). Adults with a BMI between 18.5 and 24.9 are generally considered to

soldi70 [24.7K]

Answer: 0.1797

Step-by-step explanation:

Given : $\mu=24.5\ \ ; \sigma=1.2$

Let x be the random variable that represents BMI for adults in this country.

We assume that BMI for adults in this country is normally distributed.

Then, z-score for x=25.6 , $\because z=\dfrac{x-\mu}{\sigma}$

$\Rightarrow\ z=\dfrac{25.6-24.5}{1.2}\approx0.9167$

Using z-value table , we have

The probability that the person's BMI is more than 25.6 :

$P(x>25.6)=P(z>0.9167)=1-P(z\leq0.9167)\\\\=1- 0.8203413=0.1796587\approx0.1797$

Hence, the probability that the person's BMI is more than 25.6 = 0.1797

Hence, the probability that the person's BMI is more than 25.6 = 0.1796

Hence, the probability of the stick's weight being 2.23 oz or greater = 0.0174

5 0

4 years ago

Sisters math question

zalisa [80]

Answer:

How does one find use partial quotients for subration

Step-by-step explanation:

7 0

3 years ago

Find the radius of a circle having area 616cm square.

OLEGan [10]

Answer:

$\boxed{\sf Radius \ of \ circle = 14 \ cm}$

Given:

Area of circle = 616 cm²

To Find:

Radius of circle

Step-by-step explanation:

$\sf \implies Area \ of \ circle = \pi r^{2} \\ \\ \sf \implies 616 = \frac{22}{7} \times {r}^{2} \\ \\ \sf \implies 616 \times \frac{7}{22} = {r}^{2} \\ \\ \sf \implies 28 \times \cancel{22} \times \frac{7} { \cancel{22}} = {r}^{2} \\ \\ \sf \implies 28 \times 7 = {r}^{2} \\ \\ \sf \implies 196 = {r}^{2} \\ \\ \sf \implies {r}^{2} = 196 \\ \\ \sf \implies r = \sqrt{196} \\ \\ \sf \implies r = \sqrt{ {14}^{2} } \\ \\ \sf \implies r = 14 \: cm$