Area=1/2 times base times height
note:bh=base times height
a=1/2bh
b=width
h=-4+2w
h=2w-4
subsitute
a=1/2w(2w-4)
a=1/2(2s^2-4w)
a=w^2-2w
a=63
63=w^2-2w
subtract 63 from both sdies
0=w^2-2w-63
factor
find what 2 numbers multiply to get -63 and add to get -2
the numbers are -9 and 7
so
0=(w-9)(w+7)
if xy=0 then x and/or y=0
so
w-9=0
w+7=0
solve each
w-9=0
add 9 to both sdies
w=9
w+7=0
subtract 7 from both sides
w=-7
width cannot be negative so this can be discarded
width=9
subsitute
l=2w-4
l=2(9)-4
l=18-4
l=14
legnth=14 in
width/base=9 in
16000000000000.
Hope it helped
Answer:
![\left(\displaystyle \sqrt[3]{x^{-\tfrac 35}}\right)^{\tfrac 58}](https://tex.z-dn.net/?f=%5Cleft%28%5Cdisplaystyle%20%5Csqrt%5B3%5D%7Bx%5E%7B-%5Ctfrac%2035%7D%7D%5Cright%29%5E%7B%5Ctfrac%2058%7D)
Step-by-step explanation:
![\left(\displaystyle \sqrt[3]{x^{-\tfrac 35}}\right)^{\tfrac 58}\\\\\\=\left[ \left(\displaystyle x^{-\tfrac 35} \right)^{\tfrac 13 \right]^{\tfrac 58}\\\\\\=\left( \displaystyle x^{-\tfrac 35}\right)^{\tfrac 5{24}}\\\\\\=x^{ \displaystyle -\tfrac{3}{24} \right}\\\\\\=x^{\displaystyle -\tfrac 18 }\\\\\\=\dfrac 1{x^{\tfrac 18}}](https://tex.z-dn.net/?f=%5Cleft%28%5Cdisplaystyle%20%5Csqrt%5B3%5D%7Bx%5E%7B-%5Ctfrac%2035%7D%7D%5Cright%29%5E%7B%5Ctfrac%2058%7D%5C%5C%5C%5C%5C%5C%3D%5Cleft%5B%20%5Cleft%28%5Cdisplaystyle%20x%5E%7B-%5Ctfrac%2035%7D%20%5Cright%29%5E%7B%5Ctfrac%2013%20%5Cright%5D%5E%7B%5Ctfrac%2058%7D%5C%5C%5C%5C%5C%5C%3D%5Cleft%28%20%5Cdisplaystyle%20x%5E%7B-%5Ctfrac%2035%7D%5Cright%29%5E%7B%5Ctfrac%205%7B24%7D%7D%5C%5C%5C%5C%5C%5C%3Dx%5E%7B%20%5Cdisplaystyle%20-%5Ctfrac%7B3%7D%7B24%7D%20%20%5Cright%7D%5C%5C%5C%5C%5C%5C%3Dx%5E%7B%5Cdisplaystyle%20-%5Ctfrac%2018%20%20%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%201%7Bx%5E%7B%5Ctfrac%2018%7D%7D)
Answer:
Cos^2x csc^2x
Step-by-step explanation:
Cos^2x (1 + cot^2x)
