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3 years ago

What is the distributive prperty to exspress 24+36

Mathematics

1 answer:

Liula [17]3 years ago

8 0

I think it would be 12(2-3)

Hope this helps!

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Y is directly proportional to x, and y =216 when x=2 find y when x=7

jek_recluse [69]

Y = kx
@ y = 216, x = 2
k = y/x = 216/2 = 108

@ x=7
y = (108)(7) = 756

5 0

3 years ago

The perimeter of a rectangular tray is 28 inches. The length of the tray is 2 inches longer the width of the tray. Determine the

fenix001 [56]

Answer:

width = 6 and length = 8

Step-by-step explanation:

perimeter = 2*(length + width). (1)

and we have that length = 2 + width

in (1)

28 = 2 *(width + 2 + width)

14= 2*width +2

width =6

and so length will be 8

8 0

3 years ago

The pattern 0.73, 083 , 0.93

soldi70 [24.7K]

Answer:

1.03

Step-by-step explanation:

I think the pattern is adding .1 So then next one is 1.03

3 0

3 years ago

Read 2 more answers

Mrs. Bhatia's closet consists of two sections, each shaped like a rectangular prism. She plans to buy mothballs to keep the moth

AveGali [126]

Answer:

6.5 boxes

Step-by-step explanation:

Given

See attachment for closet

Required

Determine the number of boxes needed to fill the closet

First, we calculate the volume of the two section.

According to the attachment

The first section has the following dimension:

$Width = 5ft$

$Length = 4ft$

$Height = 8ft$

The second has the following dimension:

$Width = 3ft$ ---- see the last label at the top

$Length = 2ft$ --- This is calculated by subtracting the length of the first section (4ft) from the total length of the closet (6ft) i.e. 6ft - 4ft

$Height = 8ft$

So: The volume of the closet is:

$Volume = W_1 * L_1 * H_1 + W_2 * L_2 * H_2$

$Volume = 5ft * 4ft * 8ft + 3ft * 2ft * 8ft$

$Volume = 160ft^3 + 48ft^3$

$Volume = 208ft^3$

The number of box needed is then calculated by dividing the volume of the closet (208ft^3) by the volume of each box (32ft^3)

$Boxes = \frac{208ft^3}{32ft^3}$

$Boxes= \frac{208}{32}$

$Boxes = 6.5$

7 0

3 years ago

Given limit of f (x) = 4 as x approaches 0. what is limit of one-fourth left-bracket f (x) right-bracket superscript 4 baseline

Otrada [13]

The limit of the given function if $\lim_{x \to 0} f(x)=4$ is 64

<h3>Limit of a function</h3>

Given the following limit of a function expressed as;

$\lim_{x \to 0} f(x)=4$

We are to determine the value of the function

$\frac{1}{4} \lim_{x \to 0} [f(x)]^4$

This can also be expressed as

$\frac{1}{4} \lim_{x \to 0} [f(x)]^4\\ = \frac{1}{4}(4)^4 \\=1/4\times 256\\=64$

Hence the limit of the given function if $\lim_{x \to 0} f(x)=4$ is 64

Learn more on limit of a function here: brainly.com/question/23935467

#SPJ1

4 0

2 years ago