All categories

3 years ago

Please help with math! Giving a thanks

Mathematics

2 answers:

Svetach [21]3 years ago

6 0

Answer:

1/4x<5-1

1/4x<4

x<16

last one

JulsSmile [24]3 years ago

5 0

Answer:

The last one is the correct answer

You might be interested in

Maria handed out 125 flyers that gave students the time and locationtry outs for the school volleyball team. What is 125 written

Temka [501]

One way is to factor and see which ones repeat

125=5*5*5
it is 5 times itself 3 times
5^3

4 0

3 years ago

Read 2 more answers

Help solve the following equation: 20.6 + 2.1x = -8.2x

Igoryamba

$20.6 + 2.1x = -8.2x$

$20.6=-10.3x$

$-2=x$

4 0

3 years ago

Read 2 more answers

Drag each situation to show whether it can be modeled using a linear or an exponential function. If the situation cannot be mode

Goshia [24]

Answer:

bihdbhdvn sfv jdn vhusrvnfg k,b snjbstdnj fcmranfbtgb,fy hje5rtgbv mdrhgsdmrmgbhedslrk cj5rtkolg segpo esjxmh9iorexdsvjbyhklycf,x n

Step-by-step explanation:

5 0

3 years ago

Please provide a solution its urgent

kakasveta [241]

Yes lil mosey is in fact white.

8 0

3 years ago

X = ? y = ? 16 45 degrees

mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

For y, we will be using the Sine Function.

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

5 0

1 year ago