Answer:
uniformly distributed random numbers here the MATLAB code to find for any number of people and interval
X = rand
X = rand(n)
X = rand(sz1,...,szN)
X = rand(sz)
X = rand(___,typename)
X = rand(___,'like',p)
where
X = rand returns a single uniformly distributed random number in the interval (0,1).
X = rand(n) returns an n-by-n matrix of random numbers.
X = rand(sz1,...,szN) returns an sz1-by-...-by-szN array of random numbers where sz1,...,szN indicate the size of each dimension. For example, rand(3,4) returns a 3-by-4 matrix.
X = rand(sz) returns an array of random numbers where size vector sz specifies size(X). For example, rand([3 4]) returns a 3-by-4 matrix.
X = rand(___,typename) returns an array of random numbers of data type typename. The typename input can be either 'single' or 'double'. You can use any of the input arguments in the previous syntaxes.
X = rand(___,'like',p) returns an array of random numbers like p; that is, of the same object type as p. You can specify either typename or 'like', but not both.
Answer:y=-1/3x+17/3
Step-by-step explanation:
Answer:
D is correct option
Step-by-step explanation:
The correct option is D.
The standard quadratic equation is ax²+bx+c=0
Where a and b are coefficients and c is constant.
It means that constant are on the L.H.S and there is 0 on the right hand side.
Therefore to make it a quadratic equation first of all you have to add 11 at both sides so that the R.H.S becomes 0.
The given equation is:
2x2-x+ 2 = -11
If we add 11 on both sides the equation will be:
2x2-x+ 2 +11= -11+11
2x^2-x+13=0
Thus the correct option is D
You can further solve it by applying quadratic formula....
Answer:
The second train speed is 356.4 miles per hour
And, the first train speed is 361 miles per hour
Step-by-step explanation:
The computation of the speed of each train is as follows
Given that
The Sum of the speed of two trains is 717.4 miles per hour
Let us suppose the second train speed be x
So for the first train, the speed is x + 4.6
Now the equation is
x + x + 4.6 = 717.4
2x + 4.6 = 717.4
2x = 717.4 - 4.6
2x = 712.8
x= 356.4
Therefore the second train speed is 356.4 miles per hour
And, the first train speed is = 356.4 + 4.6 = 361 miles per hour