How many solutions does this equation have? 1/2 + 4x = - x + 2

Mathematics

1 answer:

Ierofanga [76]3 years ago

3 0

Answer:

Step-by-step explanation:

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What is 35% of 35? please included how you got it!!

ruslelena [56]

$\huge\boxed{12.25}$

First, convert the percentage to a decimal. You can do this by moving the decimal place two places to the left.

$35\%\longrightarrow0.35$

Now, simply multiply that decimal by $35$ using a calculator.

$0.35*35=\boxed{12.25}$

4 0

4 years ago

Read 2 more answers

8.2.AP-7

siniylev [52]

Answer:

c ≈ 40

Step-by-step explanation:

Using the sine ratio in the right triangle

sin40° = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AC}$ = $\frac{26}{c}$ ( multiply both sides by c )

c × sin40° = 26 ( divide both sides by sin40° )

c = $\frac{26}{sin40}$ ≈ 40 ( to the nearest whole number )

7 0

3 years ago

What is lim x→3 x^2 - x - 6/ x - 3

Kisachek [45]

<h3>Answer: D) 5</h3>

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Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, $\frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2$

Allowing us to say,

$\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\$