Grab some paper, a pencil, and a ruler. Make a 6 by 6 square
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer:
4
Step-by-step explanation:
A-action games
s-sports games
a+s=47
a=s+21
I replace the action games in the first equation
s+21+s=47
2s+21=47
2s=47 - 21
2s=26
s=26:2
s=13 number of sport games
a=13+21
a=34 number of action games
Answer:
the longest side is 25
Step-by-step explanation:
the equation would be x+ x+1 + 7 for the 3 sides of the triangle
x + (x+1) + 7=56
combine like terms
2x+8 = 56
subtract 8 from each side
2x = 48
divide by 2
x = 24
the sides are
x=24
x+1 = 25
7
the longest side is 25
