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alina1380 [7]
3 years ago
7

What is the area of a sector with a central angle 210 and a diameter of 4.6

Mathematics
2 answers:
Irina-Kira [14]3 years ago
8 0

Answer:

9.7m^2 if it needs to be rounded

Step-by-step explanation:

gizmo_the_mogwai [7]3 years ago
5 0
Theta = 210°
r = 4.6/2 = 2.3
Area of circle = pi * r * r
= 3.14 * 2.3 * 2.3 = 16.61
Area of sector =
(theta / 360) * area of circle
= (210/360) * 16.61
= 9.69
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7. Bill and Steve both owe their mother money. Bill owes his mother $300 and plans
Free_Kalibri [48]

Answer:

5 weeks

$175

Step-by-step explanation:

Bill owes his mother $300 and plans to pay her $25 every week.

Therefore, after w weeks he has to give her mother more C = 300 - 25w, amount of money.

Steve owes his mother $550 and plans to pay her  $75 every week.

Therefore, after w weeks he has to give her mother more C = 550 - 75w, amount of money.

If after w weeks they both will owe their mother the same amount of money, then  

300 - 25w = 550 - 75w

⇒ w = 5 weeks. (Answer)

Now, the amount of money will be $(300 - 25 × 5) = $175. (Answer)

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3 years ago
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alekssr [168]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
3 years ago
Javier earns $7.50 per hour and works 20 hours per week. He wants to know how many weeks, w, he will need to work to save
disa [49]

Answer:

8 weeks

Step-by-step explanation:

So first you find out how much money he makes per week, by doing 7.5 x 20 you will find that. Now you need to find how many weeks it will take, find this by dividing 1200 by the amount he makes per week and you will end up with 8.

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