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2 years ago

Describe how you would determine the x-intercepts from the factored form of a quadratic equation

Mathematics

1 answer:

Aloiza [94]2 years ago

4 0

Answer:

Please check explanations

Step-by-step explanation:

Given the factored form, all we have to do is to equate each of the factor to zero, then solve for x

The particular value of x represents the solution that shows the value of the x-intercept

for example

In a case of a quadratic equation where we have

(x-a)(x-b) = 0

Then we can have

(x-a) = 0 or ((x-b) = 0

Then we have x = a or x = b

a and b are the x intercepts in this case

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Let the joint pdf of X andY be f(x,y) = 12e−4x−3y , x > 0, y > 0.

forsale [732]

Answer:

Step-by-step explanation:

Find attached the solution

3 0

2 years ago

The price of a share of one stock rose from $12.50 to $50. Find the percent increase.

Blababa [14]

Answer:

50-12.50= 37.50

37.50/12.50 x100% =300%

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3 years ago

Read 2 more answers

Foil: (x+9)(3x-4)

QveST [7]

QUESTION 1

The given binomial is;

$(x+9)(3x-4)$

First terms are multiplied: $x\times 3x=3x^2$

Outside terms are multiplied: $x\times -4=-4x$

Inside terms are multiplied: $9\times 3x=27x$

Last terms are Multiplied: $9\times -4=-36$

This gives us;

$=3x^2-4x+27x-36$

$=3x^2+23x-36$

QUESTION 2

We want to factor

$6r^5s+4r^4s^2-8r^2s$

The HCF is $2r^2s$

We factor to get;

$2r^2s(3r^3+2r^2s-4)$

QUESTION 3;

$x^2+x-2=0$

Split the middle term;

$x^2+2x-x-2=0$

Factor

$x(x+2)-1(x+2)=0$

$(x+2)(x-1)=0$

$(x+2)=0,(x-1)=0$

$x=-2,x=1$

The solutions are;

$x=-2$ and $x=1$

These are the x-intercepts of the graph of the function

$f(x)=x^2+x-2$

3 0

3 years ago

Select all of the products of 2.74 • 7.5

Nana76 [90]

2.74x7.5=20.55=20.550
That's all of your answers.

7 0

2 years ago

Read 2 more answers

A TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 500

nekit [7.7K]

Answer:

0.903264

Step-by-step explanation:

Given that a TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 5000 hours of use is 0.03 for a type A circuit board, 0.04 for a type B circuit board, and 0.03 for a type C circuit board.

Let A' = the event that A fails, B' = B fails and C'= C fails.

Probability that no circuit board fails = Prob (A'B'C')

= P(A')P(B')P(C') (since A,B, C are independent, their complements are independent

= (1-0.03)(1-0.04)(1-0.03)

= 0.903264

8 0

3 years ago