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mariarad [96]
3 years ago
6

What are the x-intercepts of x^2– 3x = 4?

Mathematics
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

x^2-3x=4

x^2-3x-4=0

x^2-4x+x-4=0

x(x-4)+1(x-4)=0

(x+1)(x-4)=0

x=-1,4

x- intercepts in the point (-1,0) and (4,0)

Step-by-step explanation:

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3 is the greatest common denominator
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3 years ago
Find a number C such that the polynomial p(x)= -x+4x^2+Cx^3-8x^4
Ksenya-84 [330]

Answer:

C = 2

Step-by-step explanation:

p(x)= -x+4x^2+Cx^3-8x^4 \\  \\  \because \: given \: polynmial \: has \: zero \: at \: \\x =  \frac{1}{4}  \\  \\  \implies \: p\bigg(\frac{1}{4}  \bigg) = 0...(1) \\  \\ plug \: x = \frac{1}{4} \:  in \: p(x) \: we \: find \\  \\ p \bigg(\frac{1}{4}  \bigg)  =  - \frac{1}{4} + 4  {\bigg(\frac{1}{4} \bigg)}^{2}  + c  {\bigg(\frac{1}{4} \bigg)}^{3}  - 8  {\bigg(\frac{1}{4} \bigg)}^{4}  \\  \\ 0 = - \frac{1}{4} + \cancel 4 \times   {\frac{1}{\cancel{16} } }  + c  {\bigg(\frac{1}{64} \bigg)}  - \cancel 8  \times  \frac{1}{\cancel{256} }  \\  \\0 =\cancel{ - \frac{1}{4}} + \cancel  {{\frac{1}{4} }}  + c  {\bigg(\frac{1}{64} \bigg)}  -  \times  \frac{1}{32}  \\  \\0 =  c  {\bigg(\frac{1}{64} \bigg)}  -  \frac{1}{32}  \\  \\c  {\bigg(\frac{1}{64} \bigg)} = \frac{1}{32}   \\  \\ c = \frac{1}{32}   \times 64 \\  \\ c = 2

5 0
3 years ago
Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an
ziro4ka [17]

Answer:

1) is not possible

2) P(A∪B) = 0.7

3) 1- P(A∪B) =0.3

4) a) C=A∩B' and P(C)= 0.3

b)  P(D)= 0.4

Step-by-step explanation:

1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4  . Thus the maximum possible value of P(A∩B) is 0.4

2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by

P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7

P(A∪B) = 0.7

3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3

4) the event C that the selected student has a visa card but not a MasterCard is given by  C=A∩B'  , where B' is the complement of B. Then

P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3

the probability for the event D=a student has exactly one of the cards is

P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4

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3 years ago
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kolezko [41]
I need help in life
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2 years ago
Find the domain of the rational expression: x-4/2x-6
marin [14]

Answer:

All real numbers except 3

Step-by-step explanation:

Given

\frac{x - 4}{2x - 6}

Required

Determine the domain

We start by writing the following inequality

2x - 6 \neq  0

Add 6 to both sides

2x -6 + 6 \neq = 0 + 6

2x \neq  6

Divide both sides by 2

\frac{2x}{2}\neq  \frac{6}{2}

x \neq  \frac{6}{2}

x \neq = 3

<em>As such, the domain of x is all real numbers except 3</em>

4 0
3 years ago
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