Question

Write the sum of the numbers as the product of their GCF and another sum. Include work if possible.

Answer 1

It  looks like the first thing you have to find is their GCF, ya reckon ?

The factors of  56  are  1, 2, 4, 7, 8, 13, 28, and 56 .

The factors of  64  are  1, 2, 4, 8, 16, 32, and 64 .

The common factors are  1, 2, 4, and 8 .

The greatest one is  8 .

56/8 = 7
64/8 = 8

56  plus  64 = (8 times 7)  plus  (8 times 8)

56  plus  64 =  8 times (7 plus 8)    <== that's the answer

Check it out:

56  plus  64 = 120

8 times (7 plus 8) = 8 times 15 = 120

Answer 2

Answer:

First option,

44 + 40,

∵ GCF(44,40) = 4

Also, 44 = 4 × 11,

40 = 4 × 10,

⇒ 44 + 40 = 4 × 11 + 4 × 10 = 4×(11+10)

Second option,

15 + 81,

∵ GCF(15, 81) = 3,

Also, 15 = 3 × 5,

81 = 3 × 27,

⇒ 15 + 81 = 3 × 5 + 3 × 27 = 3 × ( 5 + 27)

Third option,

13 + 52,

GCF(13, 52) = 13,

∵ 13 = 13 × 1,

Also, 52 = 13 × 4,

⇒ 13 + 52 = 13 ×1 + 13× 4 = 13 × (1+4),

Fourth option,

64 + 28,

GCF(64, 28) = 4,

∵ 64 = 4 × 16,

Also, 28 = 4 × 7,

⇒ 64 + 28 = 4 × 16 + 4 × 7 = 4 × ( 16 + 7 )