All categories

3 years ago

Answer if you want to

Mathematics

1 answer:

Vsevolod [243]3 years ago

3 0

Answer:

Step-by-step explanation:

I hope this is right if it is i hope it helps

You might be interested in

Can someone help me please?

Zinaida [17]

I think the answer is c sorry if I’m wrong

6 0

2 years ago

Helppp! Is Figure A’B’C’D’ a reflection of Figure ABCD? Explain. *

Korolek [52]

Yes. It would be a reflection over the line.

8 0

3 years ago

What are the possible values of x in x2 + 3x + 3 = 0?

stealth61 [152]

Hello,

$x^2+3x+3=0\\

\Delta=9-4*3=-3\\

x= \dfrac{-3-i*\sqrt{3}}{2} \ or\ x= \dfrac{-3+i*\sqrt{3}}{2} \\

$

3 0

2 years ago

Read 2 more answers

No clue on this need help please

maria [59]

It would be 10x5 + 3x8= 74

5 0

3 years ago

Read 2 more answers

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$

Since

$\int\limits^1_0 {x^{2} } \, dx = 13$ ,

Substituting this into the equation the equation, we have

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Learn more about definite integrals here:

brainly.com/question/17074932

4 0

2 years ago