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JulsSmile [24]
3 years ago
14

What is the radius of the base of the cylinder 42in and 36 in

Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0
Need additional information, which is the height and which is the diameter of the cylinder from the measurements supplied?  Standard forumula for locating Radius and Volume of a cylinder are as follows.

Radius=Diameter/2
rad=dia/2

Volume=Base X height
V=B*h

Base= 3.14*r*r
 
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Ribbon candy cost 2.50 per foot. How many feet can you buy if you have 11.25?
netineya [11]

Answer: your answer is 4.5

Step-by-step explanation: your answer is 4.5 because 11.25/2.50=4.5

:)

8 0
3 years ago
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Help I will be marking brainliest!<br><br> A. 65.99<br> B. 70.19<br> C. 52<br> D. 65.52
natita [175]

Answer:

65.992

Step-by-step explanation:

LM/PL = RN/QR

LM / 113 = 73/ 125

LM =(73/125) * 113

5 0
3 years ago
Read 2 more answers
Solve using long division <br> Please
madreJ [45]

1. Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}

Steps:

\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}

\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}

\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}

\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}

\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}

2. Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}

Steps:

\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}

\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}

\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

4 0
3 years ago
How many inches of square paper did Benjamin use to wrap the box?
Dominik [7]
Two times the length of the longest edge.
5 0
3 years ago
Let x and y be any numbers at all with x ≤ y. Show that the number of integers between x and y is [y] - [x] +1.That is show that
ddd [48]

Answer:

the explanation is given below.

Step-by-step explanation:

  • Here what is applied is assumption of range of values of number from say 1 - 100
  • In total, i stopped at 100 on the dot.

from this, the lowest number is 1 and the highest number is 100

  • hence the range of the numbers = Difference between Highest and Lowest
  • range = 100 - 1 = 99, the 99 gotten as the range is indicative that a number has been missing.

  • In order to make up the 100, an integer is added to the difference = 99, i.e 99 is added to 1 to make up the 100.

  • Furthermore, if 0 is exclusively out when numbers are counted up 100 with 0 inclusive, in such case, the first and last number are excluded from the counting. as such the integers will be {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20.........., 99} since both 0 and 100 are not included.

  • Here, if we try to get the range = highest - lowest = 99 - 1 = 98, it implies that to make up the 99, an integer is added to the result of the difference = 98+1 = 99

  • As such, the number of integers between two numbers is the difference between the highest and the lowest number plus 1 i.e highest - lowest + 1 = y - x +1 = (the floor of y) - ( the ceiling of x) + 1
5 0
3 years ago
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