Major help needed !! pls ASAP

Eagle Outfitters is a chain of stores specializing in outdoor apparel and camping gear. They are considering a promotion that in

schepotkina [342]

Answer:

a) Alternative hypothesis: the use of the coupons is isgnificantly higher than 10%.

Null hypothesis: the use of the coupons is not significantly higher than 10%.

The null and alternative hypothesis can be written as:

$H_0: \pi=0.1\\\\H_a:\pi>0.1$

b) Point estimate p=0.13

c) At a significance level of 0.05, there is not enough evidence to support the claim that the proportion of coupons use is significantly higher than 10%.

Eagle should not go national with the promotion as there is no evidence it has been succesful.

Step-by-step explanation:

The question is incomplete.

The sample data shows that x=13 out of n=100 use the coupons.

This is a hypothesis test for a proportion.

The claim is that the proportion of coupons use is significantly higher than 10%.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.1\\\\H_a:\pi>0.1$

The significance level is 0.05.

The sample has a size n=100.

The point estimate for the population proportion is the sample proportion and has a value of p=0.13.

$p=X/n=13/100=0.13$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.1*0.9}{100}}\\\\\\ \sigma_p=\sqrt{0.0009}=0.03$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.13-0.1-0.5/100}{0.03}=\dfrac{0.025}{0.03}=0.833$

This test is a right-tailed test, so the P-value for this test is calculated as:

$\text{P-value}=P(z>0.833)=0.202$

As the P-value (0.202) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the proportion of coupons use is significantly higher than 10%.

6 0

3 years ago

A Car is traveling westward with a constant velocity of 20 m/s, what is the net force acting on the car?

gtnhenbr [62]

According to Newton's second law of motion, the force acting on an object is equal to the mass multiplied by the acceleration of the moving object. Since the object is moving in a constant velocity, acceleration is zero. Hence regardless of the mass of the car, the force acting is zero provided that air resistance and friction is negligible

8 0

4 years ago

The Pharmacy dispensing unit Depriciated in value by 25% during the first year unit was purchased for 28,000 what is the dispens

luda_lava [24]

25% of 28,000 is 7,000.
If the unit depreciated by 7,000, it is now worth 21,000.

5 0

3 years ago

Are these ratios proportional? prove it 5/9 = 25/18 the / are fractions

Natali [406]

5/9 = 25/18

Cross multiply:

5 * 18 = 9 * 25

Simplifying

5 * 18 = 9 * 25

Multiply 5 * 18

90 = 9 * 25

Multiply 9 * 25

90 = 225

Solving

90 = 225

No they are not

7 0

3 years ago

Read 2 more answers

Tanya made 75 flyers for five volunteers in her club to hang up around her school she gave 15 flyers to the first volunteer 22 f

AysviL [449]

Answer:

The remaining volunteers would get 11 flyers each.

Step-by-step explanation:

Given:

Total number of flyers = 75

Total number of volunteers = 5

Number of flyers for 1 volunteer = 15 flyers.

Number of flyers to 2nd volunteer = 22 flyers.

number of flyers to 3 volunteer = 16 flyers.

We need to find the remaining number of which are equally distributed in remaining number of volunteers.

Solution:

First we will find the number of flyers already distributed.

number of flyers already distributed is equal to sum of Number of flyers for 1 volunteer, Number of flyers for 2 volunteer and Number of flyers for 3 volunteer.

framing in equation form;

number of flyers already distributed = $15+22+16 = 53\ flyers$