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Hunter-Best [27]
3 years ago
7

HARDEST MATH EVER!!! 0+0= ____

Mathematics
1 answer:
Marianna [84]3 years ago
6 0

Answer:

0

Step-by-step explanation:

hehehehhehehehhehehehehhehebebe

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A rectangle has an area of 36 inches squared. Write an equation to show how the length (l) varies inversely the width (w).
Anastaziya [24]
Start with the first sentence, and the definition of the area of a rectangle:
l * w = 36

Rewrite the equation to get
l = 36 / w
or
w = 36 / l
Either one shows the inverse relationship between w and l.

Assuming the last part wants you to write an equation for an x-y graph, the equation would be
y = 36 / x
8 0
3 years ago
The product of four different positive integers is 100. What is the sum of these four integers?
Leno4ka [110]

Step-by-step explanation:

The Answer for the above question is

The four integers are 1,2,5,10. And Sum of the four integers is 18 .

<u>Method : </u>

Product of four different positive integers is 100 .

<u>First</u> of all lets break the number "100"

 ⇒  100 = 50*2

 ⇒ 100 = 25 * 2 * 2

  ⇒ 100 = 5 * 5 * 2 * 2

But here we get the same  integers 2 and 5 and we want different positive integers . So hereby merge 5 * 2  which is 10.

Let's get to the possible combination -

  After merging 5*2 = 10 we get the answer as -

 ⇒ 100 = 1 * 2 * 5 * 10

 Here, we have 1, 2, 5, 10. these are the positive integers whose product gives 100 .

Sum of these products is -

   ⇒ Sum = 1 + 2 + 5 + 10

  ⇒  Sum = 18 .

Sum of these four Integers is 18.

5 0
3 years ago
I need help plz plz ​
Reptile [31]
It is 1/3 have a great day !!
8 0
3 years ago
Read 2 more answers
If $10,500 is deposited in a compound interest account paying 2.99% interest annually, how much will be in the account after 5 y
algol [13]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10500\\ r=rate\to 2.99\%\to \frac{2.99}{100}\dotfill &0.0299\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=10500\left(1+\frac{0.0299}{1}\right)^{1\cdot 5}\implies A=10500(1.0299)^5\implies A\approx 12166.47

5 0
3 years ago
The dimensions (width and length) of room1 have been read into two variables : width1 and length1 . The dimensions of room2 have
Lorico [155]

Answer:

Total area of the two rooms   =   (width1length1) +   (width2length2)

Step-by-step explanation:

The area of the rectangular shape is given by = Length * breadth

Therefore the area of the two rooms can be calculated using the above formula when the variables lengths and widths are given.

Area 1= Area of the first room = length * breadth=  (width1length1)

Area 2=Area of the second room = length * breadth=  (width2length2)

Total area of the two rooms = Area1 + Area 2

                                         =   (width1length1) +   (width2length2)

5 0
3 years ago
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