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koban [17]
2 years ago
8

Solve x + 5 > 8. The solution is ____

Mathematics
2 answers:
qwelly [4]2 years ago
6 0
X3 -10x2 + 25x - 8 (evaluated)
professor190 [17]2 years ago
4 0
What do you mean?
Expand your question
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Six less than three times a number. write an algebraic expression to represent the given phrase
Masja [62]

Answer: 3x-6

Step-by-step explanation:

Let the number be x

3 times the number is 3x

6 less than 3x is 3x-6

4 0
3 years ago
Three times a number plus twice another is 10, while their sum is 10, Find the numbers
Aleks [24]
3a+2b=10 \\\\ a+b=10 \\\\ \boxed{a=10-b} \\\\ 3(10-b)+2b=10 \\\\ 30-3b+b=10 \\\\ -b=10-30 \\\\ -b=-20 \\\\ \boxed{b=20} \\\\ a=10-20 \\\\ \boxed{a=-10}
5 0
3 years ago
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
2 years ago
Will (-2)^2 and -2^2 have the same solution? why or why not
nexus9112 [7]
Doing this so I can ask sorry
5 0
3 years ago
Luz earns $400 for 40 hours of work. Use a ratio table to determine how much she earns for 6 hours of work.
LiRa [457]
To work out how much Luz earns, you simply have to follow 400/40=10, so she earns $10/hour. We can therefore establish that if she works for 6 hours, she'll earn $60.
7 0
3 years ago
Read 2 more answers
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