All categories

2 years ago

What is the perimeter of a square, if the area is 9 square units?

Mathematics

1 answer:

lora16 [44]2 years ago

4 0

What dkksbsjs s sbdbndd

You might be interested in

Line p contains point (6, -5) and is perpendicular to line q. The equation for line q is y = 3x + 5. 1) Write an equation for li

wel

Answer:

$y = -\frac{1}{3}x -3$

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes. To find the line, convert the slope of q and substitute it with (6, -5) into point slope form.

y = 3x + 5 is q. It has a slope of 3. So p will have a slope of -1/3.

$y - y_1 = m(x-x_1)\\y - -5 = -\frac{1}{3}(x - 6)\\y + 5 = -\frac{1}{3}x + 2\\y = -\frac{1}{3}x -3$

4 0

2 years ago

What point on the graph of y = 0.5f(x) corresponds to (4, 16)? Explain.

SVETLANKA909090 [29]

We are given a coordinate (4,16).

Where first coordinate is the value of x and second coordinate is the value of y for the function y=f(x).

We need to find the value of given point (4,16) for function y= 0.5f(x).

Here function f(x) is being multiplied by 0.5.

On multiplying 0.5 by y, it will effect the value of y only. It does not effect value of x . Because x value is still x. Only function f(x) is being multiplied by 0.5.

Therefore, y= 0.5f(4) = 0.5 * 16 = 8.

So, (4,8) is the point on the graph of y = 0.5f(x) corresponds to (4, 16).

4 0

3 years ago

What is the answer to the question

S_A_V [24]

The equation of the parallel line is y = –2x – 11.

Solution:

Given equation of the line is y = –2x – 5.

Slope of this line is $(m_1)$ = –2

To write the equation parallel to this line and passes through (–4, –3).

If two lines are parallel, then they have the same slope.

$\Rightarrow m_1=m_2$

$\Rightarrow m_2 =-2$

Point-slope formula:

$y-y_1=m(x-x_1)$

Substitute the given values in the formula, we get

$y-(-3)=-2(x-(-4))$

$y+3=-2(x+4)$

$y+3=-2x-8$

Subtract 3 from both sides of the equation.

$y+3-3=-2x-8-3$

$y=-2x-11$

Hence the equation of the parallel line is y = –2x – 11.

5 0

3 years ago

What is the nth term of the geometric sequence 4, 8, 16, 32, ... ?

Morgarella [4.7K]

Geometric is
$a_n=a_1r^{n-1}$
an=nth term
a1=first term
r=common ratio
n=which term

commmon ratio is like
a1 times r=a2
4 to 8
4 times 2=8
r=2
first term is 4
therefor

$a_n=4(2)^{n-1}$
the nth term is $4(2)^{n-1}$

3 0

3 years ago

PLease helppppppppp <img src="https://tex.z-dn.net/?f=-2x%5E4%2A%28x%5E-4%29%5E2" id="TexFormula1" title="-2x^4*(x^-4)^2

Readme [11.4K]

Answer:

No sepo ingles

Step-by-step explanation:

5 0

2 years ago