Answer:
The repulsive force is
.
Step-by-step explanation:
Consider the provided information.
The coulomb's law to calculate the repulsive force: 
Where the value of k is 9.00×10⁹ Nm²/C²
Substitute the respective values in the above formula.
![F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{[(13 cm)(\frac{1m}{100cm} )]^2}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B9%5Ctimes10%5E9%5Cfrac%7BN%5Ccdot%20m%5E2%7D%7Bc%5E2%7D%20%5Ctimes%28-24%5Ctimes10%5E%7B-9%7DC%29%5E2%7D%7B%5B%2813%20cm%29%28%5Cfrac%7B1m%7D%7B100cm%7D%20%29%5D%5E2%7D)



Hence, the repulsive force is
.
Answer:
The probability that the proportion of freshmen in the sample of 150 who plan to major in a STEM discipline is between 0.29 and 0.37 is 0.3855
Step-by-step explanation:
The probability that the proportion of freshmen in the sample of 150 who plan to major in a STEM discipline is between 0.29 and 0.37 can be calculated by finding <em>z-scores</em> and subtracting P(z<z(0.29)) from P(z<z(0.37))
z-score in the binomial distribution of 28% of freshmen entering college in a recent year planned to major in a STEM discipline can be calculated using the equation:
where
- p(s) is proportion of freshmen we are interested (0.37, 0.29)
- p is the proportion found in recent year found by research group (28% or 0.28)
- N is the sample size (150)
Then z(0.37)=
≈ 2.4550 and P(z<2.4550)=0.993
z(0.29)=
≈ 0.2728 and P(z<0.2728)=0.6075
Then P(z(0.29)<z<z(0.37))=0.993-0.6075=0.3855
Using the Pythagorean theorem:
AC = √(13^2 - 12^2)
AC = √(169 -144)
AC = √25
AC = 5 cm