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astraxan [27]
3 years ago
7

How many 1/5 liter glasses can fill with 1 1/2 liter bottle of water?

Mathematics
1 answer:
levacccp [35]3 years ago
6 0

Answer:

7 glasses/bottles :)

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Write 0.941 with word name
jolli1 [7]
Nine tenths, four hundredths, and one thousandth.

OR:

Nine hundred and forty one thousandths.
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3 years ago
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a truck can be rented from company a for $90 a day plus $0.40 per mile. company b charges $50 a day plus $0.80 per mile to rent
Neporo4naja [7]
101 miles.
truck A $130.4
truck B $130.8
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4 years ago
Y varies directly with x,and y=7 when x=2. What is the value of y when x=5?
Travka [436]
Y=10 bc y-x=5 then 5+5= 10
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3 years ago
NEED HELP!!! Please answer the question! WILL GIVE BRANILY! 15 POINTS!!!
rewona [7]

Answer: D. Cannot be determined.

If Angle 3 were not included, the answer would be A, 360°

Step-by-step explanation: When the lines a, b, & c are parallel, the line intersecting them forms angles that are vertical, supplementary and/or corresponding and congruent.

Here, angles 4 and 5 are supplementary. No need to know their exact measurements. Together, their sum is 180°

Angles 1 and 2 are also supplementary, another 180°

But we don't know the measure of angle 3, so getting an exact sum is impossible here.

5 0
3 years ago
If you start with 85 milligrams of Chromium 51, used to track red blood cells, which
zysi [14]

About 92 days are taken for 90 % of the material to <em>decay</em>.

The mass of radioisotopes (m), measured in milligrams, decreases exponentially in time (t), measured in days. The model that represents such decrease is described below:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

  • m_{o} - Initial mass, in milligrams.
  • m(t) - Current mass, in milligrams.
  • \tau - Time constant, in days.

In addition, the time constant is defined in terms of half-life (t_{1/2}), in days:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m_{o} = 85\,mg, t_{1/2} = 27.7\,d and m(t) = 8.5\,mg, then the time required for decaying is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{27.7\,d}{\ln 2}

\tau \approx 39.963\,d

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}

t\approx 92.018\,d

About 92 days are taken for 90 % of the material to <em>decay</em>.

We kindly invite to check this question on half-life: brainly.com/question/24710827

8 0
2 years ago
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