Answer:
Step-by-step explanation:
y = a * x(x - 3)(x + 1)^2
2,12 is used to find the value of a
y = a (2)(2 - 3)(2 + 1)^2
12 = a (2)(-1)(3)^2
12 = a (2) (-1) (9)
12 = - 18*a
12/-18 = a
a = - 2/3
y = (-2/3)*x*(x - 3)(x + 1)^2
Answer:
No real solutions.
Step-by-step explanation:


I'm going to subtract the second expression for y and plug it into the first equation.
So solving x=y+8 for y by subtracting 8 on both sides gives us y=x-8.
I'm going to insert this for the first y like so:

Now I'm going to move everything to one side.
I'm going to subtract x on both sides and add 8 on both sides.

Simplifying:

Now our job since the coefficient of x^2 is 1 is to find two numbers that multiply to be 4 and at the same time add up to be -3. I can't think of any such numbers.
Let's check the discriminant.
Compare
to
.
So
.
The discriminant is
.
So plugging in our numbers we get
.
Time to simplify:



So since the discriminant is negative, then the solutions will not be real.
Step-by-step explanation:
you're just going to switch x and y and then solve for y
Answer: n = -rt/10 + 1/10
Explanation: isolate the variable by dividing each side with the factors that don’t contain n, then isolate n to get this answer.
Hope this helps!