Answer:
(a - 3) • (a - 4)
Step-by-step explanation:
The first term is, a2 its coefficient is 1 .
The middle term is, -7a its coefficient is -7 .
The last term, "the constant", is +12
Multiply the coefficient of the first term by the constant 1 • 12 = 12
Find two factors of 12 whose sum equals the coefficient of the middle term, which is -7 .
-12 + -1 = -13
-6 + -2 = -8
-4 + -3 = -7 That's it
Rewrite the polynomial splitting the middle term using the two factors, -4 and -3
a2 - 4a - 3a - 12
Add up the first 2 terms, pulling out like factors :
a • (a-4)
Add up the last 2 terms, pulling out common factors :
3 • (a-4)
Add up the four terms
(a-3) • (a-4)
Really hope this helps :)
If you were to convert 3/4 and 4/5 to have the same denominator it would be 15/20 and 16/20.
Now we compare. This should be easy...
Its 4/5 or 16/20.
Let's solve your inequality step-by-step.
<span><span><span>5x</span>+3</span>><span><span>4x</span>+7
</span></span>Step 1: Subtract 4x from both sides.
<span><span><span><span>5x</span>+3</span>−<span>4x</span></span>><span><span><span>4x</span>+7</span>−<span>4x
</span></span></span><span><span>x+3</span>>7
</span>Step 2: Subtract 3 from both sides.
<span><span><span>x+3</span>−3</span>><span>7−3
</span></span><span>x>4
</span>Answer:
<span>x><span>4</span></span>
The Answer Would Be 178 .
Answer:
<em>1) y = (x-3)²-12</em>
<em>2) y = 5(x-2)²-9 </em>
Step-by-step explanation:
Given the quadratic expressions
y=x²-6x-3
We are to transform it in the form y=ax²+bx+c
y=(x²-6x)-3
Complete the square of the expression in parenthesis
y = (x²-6x + (6/2)² - (6/2)²)-3
y = (x²-6x+3²-3²)-3
y = (x²-6x+9-9)-3
y = (x²-6x+9)-12
y = (x²-3x-3x+9)-12
y = x(x-3)-3(x-3)-12
y = (x-3)(x-3)-12
y = (x-3)²-12
Hence the transformation is y = (x-3)²-12 where a = 1 and k = -12
For the quadratic equation
y=(5x²-20x)-5
y = 5(x²-4x)- 5
Complete the square of the expression in parenthesis
y = 5(x²-4x+4-4)- 5
y = 5(x²-4x+4)-9
y = 5(x-2)²-9
<em>Hence the transformation is y = 5(x-2)²-9 where a = 5 and k = -9</em>
