Answer:
Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by
where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:
reduce fraction:
By using calculator we acquire:
hence, the remaining sample after 420 days is 0.625 kg
Answer:
Step-by-step explanation:
x = time
y = elevation
At x = 0 , y = 0
It takes the submarine 2 hours to make descent of 2100 ft
=> x = 2 , y = - 2100
Slope = ( -2100 - 0)/(2 - 0) = -1050
y - 0 = -1050 ( x -0)
=> y = -1050x
1050x + y = 0
represent the relationship between the submarine's elevation and time.
Answer:
Assuming it is (4x4)^2, it is 64.
Step-by-step explanation:
The 4x4 part can basically add 1 to the exponent because you are multiplying a number by itself, and 4^3 is 64.
Order the number:
15,34,71,75,75,78,78,78,82,90,90,94,100
Mode:78
Mean≈74.8
Median:78 is your final answer. Hope it help!
For this case we have the following quadratic functions:
Revenue: 
Cost: 
Then, we observe that the profit is given by the following mathematical relationship:
Substituting values we have:
Making the corresponding calculations we have:
Answer:
An expression that represents the profit is:
