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NISA [10]
2 years ago
10

Devide (a2+ 7a+ 12)÷ (a+3)​

Mathematics
1 answer:
arlik [135]2 years ago
5 0

Answer:

(a - 3) • (a - 4)

Step-by-step explanation:

The first term is,  a2  its coefficient is  1 .

The middle term is,  -7a  its coefficient is  -7 .

The last term, "the constant", is  +12

Multiply the coefficient of the first term by the constant   1 • 12 = 12

Find two factors of  12  whose sum equals the coefficient of the middle term, which is   -7 .

     -12    +    -1    =    -13

     -6    +    -2    =    -8

     -4    +    -3    =    -7    That's it

Rewrite the polynomial splitting the middle term using the two factors, -4  and  -3

                    a2 - 4a - 3a - 12

Add up the first 2 terms, pulling out like factors :

                   a • (a-4)

             Add up the last 2 terms, pulling out common factors :

                   3 • (a-4)

Add up the four terms

                   (a-3)  •  (a-4)

Really hope this helps :)

           

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