Tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)*(tan b) ];
let be a = 2x and b = x;
=> tan 3x = [ tan 2x + tan x ] / [ 1 - (tan 2x)*(tan x) ] => (tan 3x)*[ 1 - (tan 2x)*(tan x) ] =
tan 2x + tan x => tan3x - tan 3xtan 2xtanx = tan 2x + tan x => <span> tan 3x−tan 2x−tanx = tan 3xtan 2xtanx.</span><span />
Answer:
(2)
Step-by-step explanation:
Ok i tried and ig youre looking for what a and b equal for both systems..... it'll be 1) a=-2b+15 b=7.5-(1/2)a <-- fraction........2) a=-6+b b=6-a
