Answer:
The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the <u>line y = x</u> and a translation <u>10 units right and 4 units up</u>, equivalent to T₍₁₀, ₄₎
Step-by-step explanation:
For a reflection across the line y = -x, we have, (x, y) → (y, x)
Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x
The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)
Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'
Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎
Question: 2x - 4 + 5x
Simplified: 7x - 4
<h2>C. ΔQRS ≅ ΔGFE </h2>
ΔQRS ≅ ΔGFE because :
∠Q = ∠G = 55°( corresponding part )
∠R = ∠F = 60° ( corresponding part )
∠S = ∠E = 65° ( corresponding part )
QS = GE = 16 ( corresponding part )
Therefore , the correct answer is :-
<h3>C. ΔQRS ≅ ΔGFE </h3>
