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3 years ago

After his alarm rings, Clarence has

Mathematics

1 answer:

Sonja [21]3 years ago

7 0

Answer: 14 days

Step-by-step explanation:

Day 1: 1 minute snooze = 24 minutes

Day 2: 2 minute nooze = 23 minutes ; these examples show snooze time = days.

We can set up an equation for this situation: 25 - s = r ; where s = snooze time and r = time to get ready.

Given the problem, we can fill out this equation with: 25 - s = 11

When you solve this equation, time snoozed = 14.

We already know that snooze time = days, so days = 14.

I am not a professional, simply using prior knowledge!

Note- It would mean the world to me if you could mark me brainliest!

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A piece of aluminum that is 20 cm³ has a mass of 54 g.<br> a. What is the density of the aluminum?

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2.7 grams/ cm ³ , it will float

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3 years ago

Multiply out (expand) the following bracket<br> 5(x - 3)

kifflom [539]

Step-by-step explanation:

5x - 15 we multiply the barclet value by 5

4 0

3 years ago

Read 2 more answers

A. Student GPAs: Bob’s z-score z = + 1.71 μ = 2.98 σ = 0.36 b. Weekly work hours: Sarah’s z-score z = + 1.18 μ = 21.6 σ = 7.1 c.

hjlf

Answer:

a) $x = \mu +z*\sigma$

And replacing we got:

$x= 2.98 + 1.71*0.36 = 3.5956$

b) $x = \mu +z*\sigma$

And replacing we got:

$x= 21.6 + 1.18*7.1 = 29.978$

c) $x = \mu -z*\sigma$

And replacing we got:

$x= 150 - 1.35*40= 96$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = 1.71, \mu = 2.98,\sigma = 0.36$

If we solve for x from the z score formula we got:

$x = \mu +z*\sigma$

And replacing we got:

$x= 2.98 + 1.71*0.36 = 3.5956$

Part b

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = 1.18, \mu = 21.6,\sigma = 7.1$

If we solve for x from the z score formula we got:

$x = \mu +z*\sigma$

And replacing we got:

$x= 21.6 + 1.18*7.1 = 29.978$

Part c

Let X the random variable of interest for this case. We define the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

And for this case we know that $z = -1.35, \mu = 150,\sigma = 40$

If we solve for x from the z score formula we got:

$x = \mu -z*\sigma$

And replacing we got:

$x= 150 - 1.35*40= 96$

5 0

3 years ago

A cheese can be classified as either raw dash milk or pasteurized. Suppose that 91% of cheeses are classified as pasteurized.

Marina CMI [18]

Answer:

Step-by-step explanation:

Given that a cheese can be classified as either raw dash milk or pasteurized. Suppose that 91% of cheeses are classified as pasteurized.

Each cheese is independent of the other and there are only two outcomes.

Hence X = no of cheeses pasteurized is binomial (2,0.91)

a) P(x=2 ) when n=2 is $(0.91)^2=0.8281$

b) n=6.

P(x=6) = $(0.91)^6=0.5679$

c) P(atleast one raw dash milk) = 1-P(all pasteurised)

=0.8281

Since probability is 0.83 it is not unusual.

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3 years ago

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Answer:

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3 years ago