1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pshichka [43]
3 years ago
15

How are the nominees selected?

Mathematics
2 answers:
bekas [8.4K]3 years ago
6 0

Please make the questions more clear

____________________________________________________________

Oliga [24]3 years ago
6 0

Answer:

could you make the question more understandable?

Step-by-step explanation:

sorry

You might be interested in
Based on the graph shown, which subject group shows the greatest increase in signal response?
olchik [2.2K]
C, not only is it visibly the steepest, it also, if you look at the numbers, rises the most.
7 0
4 years ago
Read 2 more answers
Please help! see attached
nikdorinn [45]

Answer:

  1. The lowest value of the confidence interval is 0.5262 or 52.62%
  2. The highest value of the confidence interval is 0.5538 or 55.38%

Step-by-step explanation:

Here you estimate the proportion of people in the population that said did not have children under 18 living at home.It can also be given as a percentage.

The general expression to apply here is;

C.I=p+-z*\sqrt{\frac{p(1-p)}{n} }

where ;

p=sample proportion

n=sample size

z*=value of z* from the standard normal distribution for 95% confidence level

Given;

n=5000

<u>Find p</u>

From the question 54% of people chosen said they did not have children under 18 living at home

\frac{54}{100} *5000 = 2700\\\\p=\frac{2700}{5000} =0.54

<u>To calculate the 95% confidence interval, follow the steps below;</u>

  • Find the value of z* from the z*-value table

The value of z* from the table is 1.96

  • calculate the sample proportion p

The value of p=0.54 as calculated above

  • Find p(1-p)

0.54(1-0.54)=0.2484

  • Find p(1-p)/n

Divide the value of p(1-p) with the sample size, n

\frac{0.2448}{5000} =0.00004968

  • Find the square-root of p(1-p)/n

=\sqrt{0.00004968} =0.007048

  • Find the margin of error

Here multiply the square-root of p(1-p)/n by the z*

=0.007048*1.96=0.0138

The 95% confidence interval for the lower end value is p-margin of error

=0.54-0.0138=0.5262

The 95% confidence interval for the upper end value is p+margin of error

0.54+0.0138=0.5538

7 0
3 years ago
Read 2 more answers
Screenshot down below math question
Volgvan

I believe the answer is 1.35 x10^14

8 0
3 years ago
Giselle deposited $3500 into a savings account for which simple interest is
valentina_108 [34]
It wouls be C since its property portions
7 0
3 years ago
Read 2 more answers
Find the product for 2(2n + 3)
pogonyaev

Answer:

4n+6

Step-by-step explanation:

7 0
3 years ago
Other questions:
  • A 2007 U.S. study by Fontana, Klein, and Holloszy compared a number of factors associated with heart disease and metabolic disor
    14·1 answer
  • Given a mean of 52.3 and a standard deviation of 1.8, what is the z-score of the value 51.8 rounded to the nearest tenth?
    5·1 answer
  • Answer for both for brainliest
    5·1 answer
  • What is -23÷6 please show work
    14·2 answers
  • I need the answer fat im runnin out of time
    5·1 answer
  • 20.5 into a percent
    10·1 answer
  • Brenda knows that there are 16 ounces and two cups what is the ratio ounces to cups
    14·2 answers
  • Anyone know this ?? thanks
    6·1 answer
  • Find the missing side lengths. Leave your answers as radicals in simplest form. *
    14·1 answer
  • Help!! I’ll mark brainly list but explain
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!