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3 years ago

Find the missing length. Round your answer to the nearest tenth.

Mathematics

2 answers:

Jobisdone [24]3 years ago

5 0

Answer: D. 9.4 units

Explanation: We use the Pythagoras theorem because we know that it’s a right triangle and we have 2 lengths.

8^2+5^2= c^2

89=c^2
c= sqrt 89
c≈9.4 units

cluponka [151]3 years ago

3 0

Answer:A

Step-by-step explanation:

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Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

Definition

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

Definition II

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

Examples

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

Absolute Value Property I

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

Conclusion

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

2 years ago

Read 2 more answers

Multiply the polynomials.

slavikrds [6]

(x + 3)(x² – 6x + 5)= x³-6x²+5x+3x²-18x+15 =x³ -3x²-13x+15 Answer B

4 0

2 years ago

Read 2 more answers

Given f(x)=x3 and g(x)= 1-5x2, fine (fog)(x) and it’s Domain

andre [41]

Answer:

Option B. $f(g(x)) = (1-5x ^ 2) ^ 3$ all real numbers

Step-by-step explanation:

We have

$f(x) = x ^ 3$ and $g(x) = 1-5x ^ 2$

They ask us to find

(fog)(x) and it's Domain

To solve this problem we must introduce the function g(x) within the function f(x)

That is, we must do f(g(x)).

So, we have:

$f(x) = x ^ 3$

$g(x) = 1-5x ^ 2$

Then:

$f(g(x)) = (1-5x ^ 2) ^ 3$

The domain of the function f(g(x)) is the range of the function $g(x) = 1-5x ^ 2$ .

Since the domain and range of g(x) are all real numbers then the domain of f(g(x)) are all real numbers

Therefore the correct answer is the option b: $f(g(x)) = (1-5x ^ 2) ^ 3$

And his domain is all real.

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3 years ago

Read 2 more answers

What is the standard deviation of the data set given below? 4,7, 8, 9, 12

larisa [96]

Answer:

I think 7

Step-by-step explanation:

4 , 8 , 9 and 12 has factors.

7 has no factor.

4= 2×2

8= 2×4

9= 3×3

12= 3×4

3 0

3 years ago

The students at Norton School were asked to name their favorite type of pet. Of the 430ilar results, about students surveyed, 25

elena-s [515]

Answer: 60

Step-by-step explanation:

From the question, we are informed that 430 students were surveyed and 258 said that their favorite type of pet was a dog. The fraction/decimal of those that chose dog as their favorite pet will be:

= 258/430

= 3/5

= 0.6

Suppose that only 100 students were surveyed, the number of students that would say that a dog is their favorite types of pet will be:

= 0.6 × 100

= 60

5 0

3 years ago