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2 years ago

Acone has a height of 7 ft and a radius of 4 ft. Which equation can find the volume of the cone?

Mathematics

1 answer:

Marina86 [1]2 years ago

3 0

Answer:

Volume of the cone = $117.06\,feet^3$

Step-by-step explanation:

Height of the cone = $7\,feet$

Radius of the cone = $4\,feet$

Volume of a cone is:

$\pi \times r^2\times \dfrac{h}{3}$

As, $\pi =\dfrac{22}{7} =3.14$

Volume is:

$=3.14\times(4\times 4)\times \dfrac{7}{3}\\\\ =3.14\times 16 \times 2.33\\\\=3.14\times 37.28\\\\=117.06\,feet^3$

The volume of the cone is: $117.06\,feet^3$

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3 years ago

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scoundrel [369]

OK. I did it. Now let's see if I can go through it without
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I think the key to the whole thing is this fact:

   A radius drawn perpendicular to a chord bisects the chord.

That tells us several things:

-- OM bisects AB.
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-- Since AC is half of AB,
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Now look at the right triangle inside the rectangle.
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But a = b/2, so   (b/2)² + b² = r²

(b/2)² = b²/4        b²/4   + b² = r²

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Repeat the
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3 years ago

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3 years ago

Read 2 more answers

A box contains one yellow, two red, and three green balls. Two balls are randomly chosen without replacement. Define the followi

Stels [109]

Answer:

One of the balls is yellow: 0.36

At least one ball is red:0.73

Both balls are green:0.3

Both balls are of the same color:0.266

Step-by-step explanation:

To get the probability equally likely of choosing balls we use the following formula

P=# of possibilities that meet the condition / #of equally likely possibilities.

#of equally likely possibilities of the first experiment is 1+2+3=6

#of equally likely possibilities of the second experiment is 1+2+3 -1 =5 ( no replacement)

We choose 2 balls so we have to multiple or add the probability of the 2 experiments, that depends on the case

One of the balls is yellow:

1 experiment P{ One of the balls is yellow }= 1/6

2 experiment P{ One of the balls is yellow }= 1/5

P{ One of the balls is yellow }= 1/6+1/5=11/30

At least one ball is red:

1 experiment P{ One of the balls is red }= 2/6

2 experiment P{ One of the balls is red }= 2/5

P{ One of the balls is yellow }= 2/6+2/5=22/30

Both balls are green:

1 experiment P{ Both balls are green }= 3/6

2 experiment P{ Both balls are green }= 3/5

P{ Both balls are green }= 3/6*3/5=0.3

Both balls are of the same color

1 experiment P{ Both balls are green }= 3/6

2 experiment P{ Both balls are green }= 2/5

P{ Both balls are green }= 3/6*2/5=0.2

1 experiment P{ Both balls are red }= 2/6

2 experiment P{ Both balls are red }= 1/5

P{ Both balls are red }= 3/6*3/5=0.066

Both could happens so we add the probabilities

P{ Both balls are of the same color }=0.2+0.066=0.266

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