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Nata [24]
3 years ago
8

Multiply or divide. Show your work. 3n²-n/n²-1÷n²/n+1

Mathematics
1 answer:
Ugo [173]3 years ago
5 0
\frac{3n^{2} - n}{n^{2} - 1} \div \frac{n^{2}}{n + 1}
\frac{n(3n) - n(1)}{n^{2} + n - n - 1} \div \frac{n^{2}}{n + 1}
\frac{n(3n - 1)}{n(n) + n(1) - 1(n) - 1(1)} \div \frac{n^{2}}{n + 1}
\frac{n(3n - 1)}{n(n + 1) - 1(n + 1)} \div \frac{n^{2}}{n + 1}
\frac{n(3n - 1)}{(n - 1)(n + 1)} \div \frac{n^{2}}{n + 1}
\frac{n(3n - 1)}{(n - 1)(n + 1)} * \frac{n + 1}{n^{2}}
\frac{3n - 1}{n - 1} * \frac{1}{n}
\frac{3n - 1}{n(n - 1)}

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7,210 books in a library are organized into 3 rooms. there are 1,960 more books in the first room than in the second room. the n
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Step-by-step explanation:

Let there be "x" number of books in the 3rd room

Now,

2nd room has 3 times as 3rd room, so we can write:

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Also, there are 1960 MORE books in 1st room than 2nd room, so we can write:

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In total there are 7210 books in all three rooms, thus we can write:

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Now, replacing the first 2 equations in this, we get:

3x + 1960 + 3x + x = 7210

Solving for x:

3x + 1960 + 3x + x = 7210\\7x=7210-1960\\7x=5250\\x=\frac{5250}{7}\\x=750

"x" is indeed what we are looking for. Thus,

There are 750 books in the third room

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