Answer:
4 ± 1/2sqrt(x) = y
This is not a function
Step-by-step explanation:
f(x) = (8-2x)^2
y = (8-2x)^2
To find the inverse function, exchange x and y and then solve for y
x = (8-2y)^2
Take the square root of each side
±sqrt(x) = 8-2y
Subtract 8 from each side
-8±sqrt(x) = 8-8-2y
-8±sqrt(x) = -2y
Divide by -2
-8/-2± 1/2sqrt(x) = -2/-2y
4 ± 1/2sqrt(x) = y
This is not a function
For the first option, since when x is going down (to the left) the function is going up, it's not approaching 0. For the second option, since when x is going up (to the right) it's going up, it's not approaching negative infinity (negative infinity is all the way down). For the third one, since when x is going down the y values are climbing, we can assume that the function's values go to positive infinity. For the last one, since when x=0 y=0, when x=0 the function does not go to infinity
Answer:
Basically G is centeroid (intersection point all three medians) so it divides BD in the ratio of 2:1
if bd is x then 2x/3 = BG i.e 38
so GD is x/3 i.e 19
