Answer : 19.6cm
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It'd be easier to do #18 if y ou were to break it up:
14* (first term + 14th term)
Sum from n=1 to 14 of n = S = ---------------------------------
14 2
14(1+14)
= ---------------- = 7(15) = 105
2
The sum of twice that is 210. The sum of "1 from n=1 to n=14" is just 14.
The final sum is 210 + 14 = 224 (answer)
Answer:
70
Step-by-step explanation:
- for the value of difference to be largest, the minuend should be maximum(most possibly) and the subtrahend should be minimum
[in A-B=X, A is minuend and B is subtrahend ]
- so, $a.b should be maximum. as there is a condition that 4 digits should be distinct, the product will be maximum if we choose 2 maximum valued numbers from the given numbers. so, one of them should be 9 and the other should be 8.
therefore, $a.b=9*8=72
- as mentioned above, c.d$ should be minimum. this will be possible only when we choose 2 minimum valued numbers from the given numbers. so, one of them should be 1 and the other should be 2.
therefore, c.d$ = 1*2 = 2
- hence, the difference = 72-2 = 70
- thus, the largest possible value of the difference $a.b - c.d$ = 70
Answer:
A B and D
Step-by-step explanation:
Answer:
1/2
Step-by-step explanation:
.5=1/2
