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3 years ago

What is the total cost of a $12.50 item plus 6% sales tax?

Mathematics

2 answers:

xz_007 [3.2K]3 years ago

7 0

13.25 is the sales tax

Verizon [17]3 years ago

3 0

Answer: %13.56

Step-by-step explanation:

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What is the equation of the line that passes through the point (6,−4) and has a slope of -1/6

Luda [366]

Answer:

y + 4 = (-1/6)(x - 6)

Step-by-step explanation:

Apply the point-slope formula here: y - k = m(x - h) becomes

y + 4 = (-1/6)(x - 6)

6 0

3 years ago

The sum of three consecutive odd integers is-219. What is the first number in the set?

Alex73 [517]

Answer:

-75

Step-by-step explanation:

Let us consider the first odd number to be 'x'.

Thus:

1st odd number: x
2nd odd number: x+2
3rd odd number: x+3

According to the question, the sum of these three consecutive ODD numbers should be equal to -219

So,

x + x + 2 + x + 4 = -219

3x + 6 = -219

3x = -225

x = -75

3 0

3 years ago

What is the slope of the line that passes through the points (1, 2) and (3, 12)?

Molodets [167]

Answer:

Slope is 5

Step-by-step explanation:

(1, 2) and (3, 12)

m= (y2-y1)/(x2-x1)

m= (12-2)/(3-1)

m= 10/2

m= 5

3 0

3 years ago

Yolanda received her telephone bill on July 27th and paid it three weeks later. What was the date that Yolanda paid her electric

Mrrafil [7]

Answer:

the answer is c august 17

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

4. Use the process outlined in the lesson to approximate the number 2√3. Use the approximation √3 ≈ 1.732 050 8.

jeka57 [31]

Answer:

sequence of five intervals

(1) 2 < $2^{\sqrt{3} }$ < $2^{2}$

(2) $2^{1.7}$ < $2^{\sqrt{3} }$ < $2^{1.8}$

(3) $2^{1.73}$ < $2^{\sqrt{3} }$ < $2^{1.74}$

(4) $2^{1.732}$ < $2^{\sqrt{3} }$ < $2^{1.733}$

(5) $2^{1.7320}$ < $2^{\sqrt{3} }$ < $2^{1.7321}$

Step-by-step explanation:

as per question given data

√3 ≈ 1.732 050 8

to find out

sequence of five intervals

solution

as we have given that √3 value that is here

√3 ≈ 1.732 050 8 ........................1

when we find $2^{\sqrt{3} }$ ................2

put here √3 value in equation number 2

we get $2^{\sqrt{3} }$ that is 3.322

sequence of five intervals

(1) 2 < $2^{\sqrt{3} }$ < $2^{2}$

(2) $2^{1.7}$ < $2^{\sqrt{3} }$ < $2^{1.8}$

(3) $2^{1.73}$ < $2^{\sqrt{3} }$ < $2^{1.74}$

(4) $2^{1.732}$ < $2^{\sqrt{3} }$ < $2^{1.733}$

(5) $2^{1.7320}$ < $2^{\sqrt{3} }$ < $2^{1.7321}$

8 0

3 years ago