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2 years ago

What is the LCM of 4489

Mathematics

2 answers:

ExtremeBDS [4]2 years ago

5 0

Answer:

plz mark me brainliest

Step-by-step explanation:

thanks for question

vredina [299]2 years ago

4 0

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67|4489

67|67

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In the table below, x represents miles traveled and y represents the cost to travel by train.

Anastasy [175]

Answer:

The second equation is correct.

y=2.25x + 4

Step-by-step explanation:

We can systematically eliminate the others.

For equation 3 and 4, 6.5*2 and 12*x is already bigger than 8 of the first set of numbers.

For equation 1, 2*x+8.5 is also bigger than 8 from the first set.

Plugging in the values to equation 2, we always get the correct cost.

5 0

3 years ago

Read 2 more answers

SOMEONE PLEASE HELP WILL MARK BRAINLIST

ra1l [238]

Answer:

The answer is 0.005.

Step-by-step explanation:

When you divide any number by 10, you move the decimal point over to the left by 1 place.

If, for example, you were instead multiplying by 10, your answer would change to 0.5.

3 0

2 years ago

The perimeter of a rectangular store receipt is ten and five-sixths inches. If three of the sides total eight and one-half inche

serg [7]

Answer:

The measure of the fourth side is $\frac{7}{3}$ .

Step-by-step explanation:

Given as :

The Perimeter of rectangular store = ( 10 + $\frac{5}{6}$ ) inches

The measure of three sides of rectangle = ( 8 + $\frac{1}{2}$ ) inches

So, The measure of three sides = length + breadth + length

I,.e 2 L + B = ( 8 + $\frac{1}{2}$ ) inches .....1

∵ perimeter = ( 10 + $\frac{5}{6}$ ) inches

So , 2 L + 2 B = ( 10 + $\frac{5}{6}$ ) inches

Or, 2 L + B + B = ( 10 + $\frac{5}{6}$ ) inches

Or, ( 8 + $\frac{1}{2}$ ) + B = ( 10 + $\frac{5}{6}$ )

or, B = ( 10 + $\frac{5}{6}$ ) - ( 8 + $\frac{1}{2}$ )

Or, B = 10 - 8 + ( $\frac{5}{6}$ ) - $\frac{1}{2}$

or, B = 2 + $\frac{5-3}{6}$

or, B = 2 + $\frac{1}{3}$

∴ B = $\frac{6 + 1}{3}$ = $\frac{7}{3}$

Hence The measure of the fourth side is $\frac{7}{3}$ . Answer

7 0

3 years ago

What value of b will cause the system to have an infinite number of solutions?

irga5000 [103]

b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

Solution:

Need to calculate value of b so that given system of equations have an infinite number of solutions

$\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}$

Let us bring the equations in same form for sake of simplicity in comparison

$\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}$

Now we have two equations

$\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}$

Let us first see what is requirement for system of equations have an infinite number of solutions

If $a_{1} x+b_{1} y+c_{1}=0$ and $a_{2} x+b_{2} y+c_{2}=0$ are two equation

$\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ then the given system of equation has no infinitely many solutions.

In our case,

$\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}$

As for infinitely many solutions $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$

$\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}$

Hence b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

8 0

3 years ago

LA = 5x -5 B = 3 + 13 B Solve for r and then find the measure of B:

topjm [15]

Answer:

x = 9º

∠B = 40º

Step-by-step explanation:

5x-5º = 3x+13º

[add 5 to both sides]

5x = 3x+18º

[subtract 3x from both sides]

2x = 18º

[divide each side by 2]

x = 9º

/ / / / / / / / / / / / / / / / / / /

3x+13º = 3(9º)+13º=27º+13º = 40º

6 0

3 years ago

What is the LCM of 4489​

What is the LCM of 4489