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timurjin [86]
3 years ago
8

Choose the appropriate test for the following situation. A company has instituted a new work policy that it hopes will reduce th

e number of sick days used per year by its employees. You wish to test whether the mean number of sick days used by employees this year differs from the mean number of sick days used last year by all employees (which was 8.2).
a. Two-sample t-test
b. One-sample t-test
c. Two-sample prop z-test
d. Dependent sample t-test
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer:

i think it is a

Step-by-step explanation:

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If 40 wrong then I am sorry.

Step-by-step explanation:

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2 years ago
Bismuth-210 is an isotope that radioactively decays by about 13% each day, meaning 13% of the remaining Bismuth-210 transforms i
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Answer:

Approximately 76.5 mg.

Step-by-step explanation:

Given,

The initial quantity of the Bismuth-210, P = 233 mg,

Also, the rate of decay per day, r = 13 %

Thus, the quantity of the Bismuth-210 after 8 days would be,

A=P(1-\frac{r}{100})^8

=233(1-\frac{13}{100})^8

=233(1-0.13)^8

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3 years ago
Parallelogram Property: opposite angles are congruent<br><br> Solve for x
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Step-by-step explanation:

Equate the two opposite Angles

7x - 31 = 5x + 13                Subtract 5x from both sides

7x - 5x - 31 = 13                 Combine

2x - 31 = 13                        Add 31 to both sides

2x = 13 + 31                       Combine the right

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3 years ago
Which solid has six faces, four lateral faces, two bases, eight vertices, and 12 edges? square pyramid triangular prism rectangu
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*********************************************
4 0
3 years ago
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After the last ice age began, the number of animal species in Australia changed rapidly. The relationship between the elapsed ti
Anarel [89]

Answer:

Every decade, the number of species decays by a factor of 0.0834.

Step-by-step explanation:

Let be S(t) = 25,000,000\cdot 0.78^{t}, \forall t \geq 0. The decay rate per decay is deducted from the following relation:

\frac{S(t+10)}{S(t)} = \frac{25,000,000\cdot 0.78^{t+10}}{25,000,000\cdot 0.78^{t}}

\frac{S(t+10)}{S(t)} = 0.78^{t+10-t}

\frac{S(t+10)}{S(t)} = 0.78^{10}

\frac{S(t+10)}{S(t)} = 0.0834

Every decade, the number of species decays by a factor of 0.0834.

6 0
3 years ago
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