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3 years ago

This isn’t math but can someone please give me an example on how you would answer this?

Mathematics

1 answer:

Jobisdone [24]3 years ago

3 0

Answer:

So I would say something like: My living situation doesn't effect my school work I have plenty of time to do my academics. I don't travel between homes I stay in one house. And I have access to a computer and cell phone. -Your friend, Bill Cipher

Step-by-step explanation:

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What is the standard deviation of a normal distribution, whose mean is 35, in which an x-value of 23 has a z-score of -1.63?

Dvinal [7]

Answer:

7.36

Step-by-step explanation:

z-score is:

z = (x − μ) / σ

Given that z = -1.63, x = 23, and μ = 35:

-1.63 = (23 − 35) / σ

σ ≈ 7.36

6 0

3 years ago

A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of

babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization $\gamma(t) = (10\cos t, 10 \sin t, 90-5t)$

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by $\frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5)$ . The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by $v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}$

d) ON the same fashion we want to know the norm of the second derivative of $\gamma$ .

We have that $\gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0)$ so the acceleration is given by $\sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10$

6 0

3 years ago

Graph the following linear inequality

pshichka [43]

Answer:❤❤❤

Step-by-step explanation:

8 0

3 years ago

Last week a machanic worked 7 1/2 hours Work out her total pay for last week

Mariulka [41]

Answer:

£81 if she only worked for 7 1/2 hours for the entire week.

£567 if she worked for 7 1/2 hours a day for the entire week.

Step-by-step explanation:

So, she makes £10.80 an hour. £10.80 x 7 1/2 = £81. So she makes £81 every day she works for 7 1/2 hours with that rate. So she'd make £567 if she worked for 7 1/2 hours every day. OR if she only worked 7 1/2 hours in total for that week she only made £81.

Hope this helps and have a nice day!

7 0

3 years ago

What is the result of isolating x^2 in the equation below? 10x^2-36y^2=100

Setler79 [48]

X^2=10+36y^2 isolates ×^2

6 0

3 years ago

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