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3 years ago

What is the length of the missing leg?

Mathematics

2 answers:

lbvjy [14]3 years ago

7 0

A= 28.
The formula for the Pythagorean theorem is A^2 + B^2 = C^2
So plug in what you know. A^2 + 21^2 = 35^2 you get A^2+ 441 = 1225. You then take away 441 from 1225 and you get A^2 = 784. You have to find the square root of 784 which is 28. So side A is 28.

OLEGan [10]3 years ago

6 0

A=28 basically what the other person said lol..

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Log6 24 + log6 3 - log6 2

patriot [66]

$\log_6 24 + \log_6 3 - \log_6 2=\\
\log_6(24\cdot3)- \log_6 2=\\
\log_672-\log_62=\\
\log_6\dfrac{72}{2}=\\
\log_636=\\
2


$

7 0

4 years ago

Order the ratios from least to greatest<br> 16/24, 5 to 12, 6:13, 10:17, 13/28

saul85 [17]

Answer:

5/12, 6/13, 13/28, 10/17, 2/3

Step-by-step explanation:

First, simplify the ones that could be simplified.

2/3, 5 to 12, 6:13, 10:17, 13/28

<em>(okay apparently only the first could be simplified)</em>

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You can look at all of them as fractions

2/3, 5/12, 6/13, 10/17, 13/28

3 0

3 years ago

A horse race has 1313 entries and one person owns 44 of those horses. Assuming that there are no ties, what is the probability

777dan777 [17]

Answer: 0.0014

Step-by-step explanation:

Given : Number of entries in horse race = 13

Number of horses owned = 4

We assume that there are no ties .

Then , the probability that those four horses finish first, second ,third ,and fourth is given by :-

$\dfrac{4!}{^{13}P_4}=\dfrac{4!}{\dfrac{13!}{(13-4)!}}\\\\=\dfrac{4!\times9!}{13!}=.0013986013986\approx0.0014$

Hence, the required probability = 0.0014

6 0

4 years ago

A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a

UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

$P_{t}=P_{0}+500t$

Where $P_{t}$ = Population after t years

$P_{0}$ = Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = $\frac{5000}{500}$

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = $\frac{15000}{500}$

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = $\frac{35000}{500}$

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

$T_{n}=T_{0}(1+\frac{r}{100})^{t}$

$T_{n}$ = Population after t years

$T_{0}$ = Initial population

t = time in years

For double once,

Population after t years = 10000

$10000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{10000}{5000}$

$(1.05)^{t}=2$

Take log on both the sides

$log(1.05)^{t}=log2$

tlog(1.05) = log2

t = $\frac{log2}{log1.05}$

t = 14.20 years

For double twice,

Population after t years = 20000

$20000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{20000}{5000}$

$(1.05)^{t}=4$

Take log on both the sides

$log(1.05)^{t}=log4$

tlog(1.05) = log4

t = $\frac{log4}{log1.05}$

t = 28.413 years

For double thrice

Population after t years = 40000

$40000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{40000}{5000}$

$(1.05)^{t}=8$

Take log on both the sides

$log(1.05)^{t}=log8$

tlog(1.05) = log8

t = $\frac{log8}{log1.05}$

t = 42.620 years

4 0

3 years ago

3/4 of a number is 24. What's the number?

Lady_Fox [76]

Hi

3x/4 = 24
3x = 24·(4)
3x = 96
x = 96/3
x = 32

3/4 of 32 is 24

4 0

3 years ago