Y would equal -17! Good luck!
Answer:
1)Area; A = ¼πr²
Perimeter; P = πr/2 + 2r
2)A = 19.63 cm²
P = 17.85 cm
3) r = 8.885 cm
4) r = 14 cm
Step-by-step explanation:
This is a quadrant of a circle. Thus;
Area of a circle is πr². A quadrant is a quarter of a circle. Thus;
Formula for Quadrant Area is; A = ¼πr²
A) Perimeter of a circle is 2πr. Thus, perimeter of a quadrant is a quarter of the full circle perimeter.
Formula for the quadrant perimeter in the image given is;
P = 2πr/4 + 2r
P = πr/2 + 2r
B) When r is 5 cm;
A = ¼π(5)²
A = 19.63 cm²
P = π(5)/2 + 2(5)
P = 17.85 cm
C) when A is 100cm²:
¼πr² = 100
r² = 100 × 4/π
r² = 78.9358
r = √78.9358
r = 8.885 cm
D) when P = 50 cm.
50 = πr/2 + 2r
50 = (½π + 2)r
r = 50/(½π + 2)
r = 14 cm
Here's the choices...Cause i don't even know the answer to this question...
<span><span>A)Over half of the patients seen on an average day had blood type O.Eliminate</span><span>
B)Less than 1% of the patients seen on an average day had blood type AB.
</span><span>
C)Double the number of patients seen on an average day had blood type O than blood type B.
</span><span>
D)<span>On an average day they will see about the same percentage of patients with types A and B.</span></span></span>
Answer:
10 ring boxes
Step-by-step explanation:
First, we need to calculate the total surface area of each cube ring boxes
The surface area of each square boxes = 6L²
Given that L =1.5inches
Total surface area = 6(1.5)²
Total surface area = 6(2.25)
Total surface area = 13.5in²
<em>Since the question is incomplete. Let us assume the total surface area of the shipping box is 135in²</em>
<em></em>
Number of ring boxes he can ship = 135/13.5
Number of ring boxes he can ship = 10
Hence the number of ring boxes he can ship is 10 ring boxes
<em />
<u><em>NB: The total surface area of the shipping box was assumed</em></u>
<u><em></em></u>
Answer:
cos34°
sin56°
Step-by-step explanation:
Sin(2x+42)= sin90-(3x+13)
Sin(2x+42) = sin(90-13-3x)
Sin(2x+42) = sin(77-3x)
2x + 42 = 77-3x
5x. = 35
X = 7
If x = 7
cos(3x+13) = cos((3*7)+13)
cos(3x+13) = cos(21+13)
cos(3x+13)= cos34
And
sin(2x+42) = sin((2*7)+42)
sin(2x+42)= sin (14+42)
sin(2x+42) = sin56
