Answer:
-5.1x + 12.3
Step-by-step explanation:
Combine like terms: first, combine the x terms, obtaining -5.1x.
Next, combine the constants, obtaining 12.3.
The simplified expression is -5.1x + 12.3
Lets say w is the width of the flower bed. We can make an equation to find the area.
The length of the of the flower bed is (w+5) and the width is w.
To find the area we need to multiply the length(w+5) by the width(w) and set it equal to 84,
(w+5)(w)=84
w^2 +5w=84
Using the quadratic equation you get the solutions of 7 and -12. Since 7 is positive it is our width. Our length is 7+5 or 12.
Answer:
(12,-6)
Step-by-step explanation:
we have
----> inequality A
---> inequality B
we know that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
<u><em>Verify each point</em></u>
Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B
case 1) (0,-1)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 2) (0,3)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 3) (-6,-6)
Inequality A

----> is true
Inequality B

----> is not true
therefore
The ordered pair is not a solution of the system
case 4) (12,-6)
Inequality A

----> is true
Inequality B

----> is true
therefore
The ordered pair is a solution of the system (makes true both inequalities)
Answer:
Explained below.
Step-by-step explanation:
A standard abacus is a traditional method used to perform basic mathematical calculations, such as addition, subtraction, multiplication and division.
There are 5 rods on a standard abacus.
The shape of the abacus has a series of vertical rods on which a number of beads are placed.
Each bead on a particular rod is considered as 1 unit, i.e. if there are three beads on a rod, the value of that rod is 3.
The last rod on an abacus is for the unit's place, the second last rod is for the ten's place, the third last rod is for the hundredth's place, the fourth last rod is for the thousandth's place and the fifth rod is for the ten thousandth's place.