4/9 x 21/6 is this what you’re asking?
If so the answer is 1 5/9
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
Answer:
the answer is c
Step-by-step explanation:
I saw it said it was due in 5 min so i ryed to solve fastt
Hope this helps!
Answer: ITS C
Step-by-step explanation:
Answer:
no, 2 would be sitting on 1
Step-by-step explanation:
