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2 years ago

A plane leave an airport and flies due north. (more in photo)

Mathematics

1 answer:

galina1969 [7]2 years ago

6 0

Answer:

104 miles (nearest whole number)

Step-by-step explanation:

Applying Pythagorean theorem which is: c² = a² + b². Where,

c = distance between the two planes = ?

a = distance of the first plane from the airport = 80 - 1 = 79 miles

b = distance of the second plane from the airport = 68 - 1 = 67 miles

c² = 79² + 67²

c² = 10,730

c = √10,730

c = 103.585713

c = 104 miles (nearest whole number)

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olchik [2.2K]

Answer:

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Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

$P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92$

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We need to find the probability that the machine works properly. It means we have to find the value of $P(A\cap B\cap C\cap D)$ .

If two events X and Y are independent, then

$P(X\cap Y)=P(X)\times P(Y)$

Assume the probability of one part working does not depend on the functionality of any of the other parts.

$P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)$

Substitute the given values.

$P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92$

$P(A\cap B\cap C\cap D)=0.7559226$

$P(A\cap B\cap C\cap D)\approx 0.756$

Therefore, the probability that the machine works properly is 0.756.

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