Catalog # Size Package Content Price* Qty
BR1400106 6 reactions of 50 µl Reagents for coupled transcription/translation reactions
€196.00
0
BR1400101 24 reactions of 50 µl Reagents for coupled transcription/translation reactions
€591.00
0
BR1400102 96 reactions of 50 µl Reagents for coupled transcription/translation reactions
€1,864.00
Answer:
I thought if you try to do an exponent on a zero, then the answer would always be undefined...
Step-by-step explanation:
Answer:
1. D
2. B
3. A
Step-by-step explanation:
Question 1:
The pair of <JKL and <LKM can be referred to as linear pairs. They are two adjacent angles that are formed from the intersecting of two lines.
Question 2:
Given that <KLM = x°
<KML = 50°
<JKL = (2x - 15)°
According to the exterior angle theorem, exterior ∠ JKL = <KLM + KML.
2x - 15 = x + 50
Solve for x
2x - x = 15 + 50
x = 65
Therefore, <KLM = 65°
QUESTION 3:
<JKL = 2x - 15
Plug in the value of x
<JKL = 2(65) - 15
= 130 - 15
<JKL = 115°
Answer:
I think it's b or d
Step-by-step explanation:
Answer:
Eddie used the incorrect ratio for sin
Step-by-step explanation:
sinT = 
= 
= 
, then
∠ T = 
( )
