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Ilya [14]
3 years ago
13

2ND LAST QUESTION

Computers and Technology
1 answer:
pychu [463]3 years ago
3 0

Answer:

B

Explanation:

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What is the difference of using Selection Tool and Direct Selection Tool?
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The Selection tool will always select the object as a whole. Use this tool when you want to manipulate the entire object. The Direct Selection tool will always select the points or segments that make up a frame

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Which one do we use to send signals as IR light waves?
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Your search google for recipe for tonight dinner is an.example of ?​
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The example is, ethier you need cooking classes or you wish to try something new

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A program is required to three (3) numbers. calculate and print their total
podryga [215]

A program that is required to three (3) numbers. calculate and print their total is given below:

<h3>The Program</h3>

import java.util.Scanner;

public class SumAndAverage {

public static void main(String[ ] args) {

System.out.println("Enter three numbers - ");

// Accepting and finding sum of numbers.

int sum = 0;

Scanner sc = new Scanner(System.in);

for (int i = 0; i < 3; i++)

sum += sc.nextInt( );

// Printing sum and average.

System.out.println("Sum - " + sum);

System.out.println("Average - " + (sum / 3f));

}

}

The output would request three different numbers, then add them up, and display the output of the sum and then display or print their total


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5 0
1 year ago
You also learn in class that one kilobyte of computer memory will hold about 2/3 of a page of typical text (without formatting).
Travka [436]

Answer:

The flashdrive can hold 35389 400-pages-books

Explanation:

If \frac{2}{3} of a page occupies 1 kB of memory, we can calculate how much memory a book will take

2/3kB=1 page\\ x kB=400 pages\\266.67 kB=400 pages

Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.

To do the calculation, we have to know how many kilobytes are in 9 gigabytes.

There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:

Memory_{in _kilobytes}^{} =1024\frac{kilobytes}{megabytes} *1024\frac{megabytes}{gigabytes}*9=9437184 kilobytes

Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.

Books=\frac{Flash drive memory}{Filesize of a book} =\frac{9437184kilobytes}{266.67\frac{kilobytes}{book} } =35389,4 books

The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.

8 0
3 years ago
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