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Mathematics

2 answers:

Katyanochek1 [597]3 years ago

6 0

(θ‿θ)(θ‿θ)(θ‿θ)(θ‿θ)(θ‿θ)(θ‿θ)

Anastaziya [24]3 years ago

5 0

Answer:

<h2>Third option</h2>

$\log _{10}\left(20x^5\right)-1\\$

Step-by-step explanation:

$5\log _{10}\left(x\right)+\log _{10}\left(20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\\\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)\\\\5\log _{10}\left(x\right)=\log _{10}\left(x^5\right)\\\\=\log _{10}\left(x^5\right)+\log _{10}\left(20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\\\quad \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)\\\\\log _{10}\left(x^5\right)+\log _{10}\left(20\right)=\log _{10}\left(20x^5\right)\\\\$

$=\log _{10}\left(x^5\cdot \:20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1\\\\=\log _{10}\left(20x^5\right)-1$

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Answer:

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