1) 10n
10 points per game, times however many games she plays.
2) x-15=19
x=34 (b)
x=15+19
If x^2+bx+16 has at least one real root, then the equation x^2+bx+16=0 has at least one solution. The discriminant of a quadratic equation is b^2-4ac and it determines the nature of the roots. If the discriminant is zero, there is exactly one distinct real root. If the discriminant is positive, there are exactly two roots. The discriminant of <span>x^2+bx+16=0 is b^2-4(1)(16). The inequality here gives the values of b where the discriminant will be positive or zero:
b^2-4(1)(16) ≥ 0
</span><span>b^2-64 ≥ 0
(b+8)(b-8) </span><span>≥ 0
The answer is that all possible values of b are in the interval (-inf, -8]∪[8,inf) because those are the intervals where </span>(b+8)(b-8) is positive.
The median of the date is 5
To solve this, I like to use a calculator. All you have to do is divide 33 by 40. 33 divided by 40 is 0.825.
The points that are possible approximations for this system are; (2.2, -1.4) and (2.2, -1.35)
<h3>How to find the solution of a linear graph?</h3>
We are given the equations of the linear graphs as;
y = ⁷/₄x + ⁵/₂
y = ³/₄x - 3
Notice that the lines intersect each other and by definition, if the lines of the system of equations intersect, then the system has one solution. This means that the point of intersection of the lines is the solution of the system. It can be written as:
(x, y)
x is the x-coordinate .
y is the y-coordinate.
In this case, we can identify that:
- the x-coordinate of the point of intersection is between; x = 2 and x = 3
- The y-coordinate of the point of intersection is between y = -1 and y = -2
Based on the above, we can conclude that the points that are possible approximations for this system are; (2.2, -1.4) and (2.2, -1.35)
Read more about Linear Graph Solution at; brainly.com/question/14323743
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