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MrMuchimi
3 years ago
6

Simplify your answer and keep improper, if necessary.

Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0

Answer:

6

Step-by-step explanation:

i liget looked this up on calculator soup

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Enter your answers in the boxes to correctly complete this statement.
harina [27]

Answer:

349800

4

Step-by-step explanation:

First Part:

The question tells you to multiply by 10 to the power of 4.

This implies that you can move the decimal point 4 numbers to the right

When you move the decimal two numbers to the right you get 3498

Then you got to move it two more numbers to the right

3498 can also be written as 3498.0000000000 (infinite amount of zeros)

So moving the decimal two more places you get 349800

Second Part:

10^4 = 10 * 10 * 10 * 10

= 10000

Count the zeros you get 4.

3 0
3 years ago
What is the density of a brownie the shape of a cube weighing 15 grams measuring 5 cm on a side?
ipn [44]

Answer:

  0.12 g/cm³

Step-by-step explanation:

Density is the ratio of mass to volume. The volume of the brownie is the cube of its side dimension:

  V = s³ = (5 cm)³ = 125 cm³

Then the density is ...

  ρ = M/V = (15 g)/(125 cm³) = 0.12 g/cm³

The density of the brownie is 0.12 g/cm³.

5 0
3 years ago
PleaSe help!!! & explain
mafiozo [28]
A) arithmetic because it is a constant. E.g 5-2 is 3 and this is true through out the series

B) this is geometric because the ratio is constant. The ratio of each is 3. E.g 81/27= 3 and this is true through out the series

C) arithmetic because it is constant. 11-3= 8, and 8 is the answer through out the series

5 0
3 years ago
Listed below are the measured radiation absorption rates? (in w/kg) corresponding to 11 cell phones. Use the given data to const
deff fn [24]

Answer:

The minimum value is 0.51

Q_1= \frac{0.89+1.04}{2}= 0.965

Median=Q2= 1.18

Q_3= \frac{1.41+1.42}{2}= 1.415

Max = 1.49

Step-by-step explanation:

We assume the following dataset:

1.18,1.41, 1.49,1.04,1.04,0.74,0.89,1.42,1.45,0.51,1.38

We order the dataset on increasing way and we have:

0.51 0.74 0.89 1.04 1.04 1.18 1.38 1.41 1.42 1.45 1.49

The minimum value is 0.51

The first quartile Q1 can be calculated with the first 6 observations: 0.51 0.74 0.89 1.04 1.04 1.18. The Q1 would be the average between the 3rd and 4th position:

Q_1= \frac{0.89+1.04}{2}= 0.965

For the median since the number of data represent an odd number than the median would be the position in the middle (6th)

Median=Q2= 1.18

The first quartile Q1 can be calculated with the last 6 observations: 1.18 1.38 1.41 1.42 1.45 1.49. The Q1 would be the average between the 3rd and 4th position:

Q_3= \frac{1.41+1.42}{2}= 1.415

And the maximum value for this case would be:

Max = 1.49

We can see the boxplot obtained on the figure attached.

5 0
3 years ago
What is the answer and why is it the answer
Afina-wow [57]

The answer is the third answer because it is the only option where the number 45 is multiplied by something bigger than 1. If something is multiplied by something smaller than one then it will be smaller than the number multiplied.


Aka: 45x0.8 is 36, because 0.8 is smaller than one

5 0
3 years ago
Read 2 more answers
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