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Andrej [43]
3 years ago
8

11x - 21 = 56 What is X

Mathematics
2 answers:
polet [3.4K]3 years ago
8 0

Answer:

hope this helps

Step-by-step explanation:

x = 7

Brilliant_brown [7]3 years ago
8 0

Answer:

x = 7

Step-by-step explanation:

56 + 21 = 77 divided by 11 = 7

May i please get the brainiest

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(5x²—4x—3)+(—2x²+7x+10)​
natka813 [3]

Answer:

I am doing the question in the comments right now!!

Step-by-step explanation:

Bc i am doing something else

6 0
3 years ago
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AHarris Interactive survey for InterContinental Hotels & Resorts asked respondents, "When traveling internationally, do you
Sauron [17]

Answer:

a) There is a 27.89% probability that two will stick with their tour group.

b) There is a 41.81% that in at least two will stick with their tour group.

c) There is a 7.33% probability that none will stick with their tour group.

Step-by-step explanation:

For each responders, this question can only have two outcomes. Either they stick with their tour group, or they don't. So this means that we can solve this problem as binomial distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

For these problems

The survey found that 23% of the respondents stick with their tour group, so \pi = 0.23.

a. In a sample of six international travelers, what is the probability that two will stick with their tour group?

The sample has six travelers, so n = 6.

We want P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789

There is a 27.89% probability that two will stick with their tour group.

b. In a sample of six international travelers, what is the probability that at least two will stick with their tour group?

Either less than two stick with their groups, or at least two do. The sum of these probabilities is decimal 1.

So

P(X < 2) + P(X \geq 2) = 1

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084

P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735

-----

P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181

There is a 41.81% that in at least two will stick with their tour group.

c. In a sample of 10 international travelers, what is the probability that none will stick with the tour group?

Now our sample has 10 travelers, so n = 10.

We want to find P(X = 0)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.23)^{0}.(0.77)^{10} = 0.0733

There is a 7.33% probability that none will stick with their tour group.

3 0
4 years ago
Solve for a. Assume that a, b and c are not zero. abc=c
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First you would divide everything by bc on both sides to get a by it self. Then you answer will be a=c/bc
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A point H on a segment with end points B(3,-1) and Z(12,5) partitions the segment in a 5:1 ratio. Find H. Show all work
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So hmm check the picture below, so the segment BZ is split in 6 pieces, 5 go to BH and HZ takes 1

\bf \left. \qquad  \right.\textit{internal division of a line segment}&#10;\\\\\\&#10;B(3, -1)\qquad Z(12,5)\qquad&#10;ratio1=5\qquad ratio2=1\qquad 5:1&#10;\\\\\\&#10;\cfrac{BH}{HZ} = \cfrac{5}{1}\implies \cfrac{B}{Z} = \cfrac{5}{1}\implies 1\cdot B=5\cdot Z&#10;\\\\\\&#10;1(3,-1)=5(12,5)\\\\&#10;-------------------------------\\\\

\bf { H=\left(\cfrac{\textit{sum of "x" values}}{ratio1+ratio2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{ratio1+ratio2}\right)}\\\\&#10;-------------------------------\\\\&#10;H=\left(\cfrac{(1\cdot 3)+(5\cdot 12)}{5+1}\quad ,\quad \cfrac{(1\cdot -1)+(5\cdot 5)}{5+1}\right)

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Ella bought some key chains and spent a total of 24$. Each key chain cost the same whole-dollar amount. She bought between 7 and
Lady_Fox [76]
She bought 8 key chains
7 0
3 years ago
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