Answer:
3^-2 evaluates to 1/9
Step-by-step explanation:
The sum of three consecutive odd integers is 76 less then seven times the middle number. The three integers are 17, 19 and 21 respeectively
<h3><u>Solution:</u></h3>
Since each consecutive odd integer is separated by a difference of 2
Let "n" be the first integer
n + 2 be the second integer
n + 4 be the third integer
Given that the sum of three consecutive odd integers is 76 less then seven times the middle number
Which means,
The sum of ( n, n + 2, n + 4) is equal to 76 less than seven times the middle number ( 7(n + 2))
That is,
n + n + 2 + n + 4 = 7(n + 2) - 76
3n + 6 = 7n + 14 - 76
4n = 68
n = 17
So we get:
First integer = n = 17
Second integer = n + 2 = 17 + 2 = 19
Third integer = n + 4 = 17 + 4 = 21
Thus the three consecutive odd integers are 17, 19 and 21 respeectively
I was too just a couple of weeks ago. So direct variation is the constant way to variables change together. EX:
x y
1 2
2 4
3 6
Direct variation must be in the format b=ka where k is a constant. So the direct variation here could be y=2x. Understand?
uno is the answer i believe
Answer: b. 51 - 3
Step-by-step explanation:
Given, Easha has 3 less than 5 times the number of quarters (I) that Isabelle has.
Here I is the number of quarters that Isabelle has.
Then, as per given,
Number of quarters Easha has = 5 ( number of quarters that Isabelle has) -3
= 5I-3
Hence, the expression shows the number of quarters Easha has is "5I-3"
So the correct option is b.
