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blagie [28]
3 years ago
10

A dietician is planning a snack package of fruit and nuts. Each ounce of fruit will supply zero units of protein, 2 units of car

bohydrates, and 1 unit of fat, and will contain 18 calories. Each ounce of nuts will supply 3 units of protein, 1 unit of carbohydrate, and 2 units of fat, and will contain 28 calories. Every package must provide at least 9 units of protein, at least 8 units of carbohydrates, and no more than 9 units of fat. What is the least number of calories possible in a package? (Type an integer or a decimal.)
Mathematics
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

The least number of calories possible in a package is 129 calories.

Step-by-step explanation:

We can write equations to representeach requirement of the snack.

Fruit:0 protein

       2 carb

       1 fat

       18 cal

Nuts: 3 prot

        1 carb

        2 fat

        28

The amount of protein contained in the final snack will be: the sum of the amount of ounces of fruit (and nuts) times the amount of protein pero ounce of fruit(and nuts). So for N, M integers or decimals:

Protein=N*0 carbs+M*3 carbs  , this means that fruit doesn't affect protein content.

Similarly we write the other requirements as inequalities:

a.Protein≥9 → N*0+M*3≥9

b.Carbs≥8 →   N*2+ M*1≥8

c.Fat≤9    →    N*1+M*2≤9

d. Cal=N*18+M*28

From a we get M≥3

Replacing M in b, N≥2.5.

And finally we replace in c to have a maximum amount.

2.5+2*3≤9

8.5<9 so this is the least amount of ounces in a package, avaluating how many calories each component contributes:

Least amount of calories: 18*2.5+28*3=129cal

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Ksju [112]

Answer:

<h3>Mass of B in Kg = -558.44kg</h3>

Step-by-step explanation:

LET'S DO THIS!

Total mass of A, B and C = 1.95kg

Mass of A = 700 kg

Mass of B = 4x the mass of c (4 x C) which is 4c

Mass of C = ? ( let's call it C )

<h3>Adding all together </h3>

700 + 4c + C = 1.95

<h3>Add like terms</h3>

700 + 5C = 1.95

5C = 1.95 - 700

5C = -698.05

C = -698.05 ÷ 5

<h3>C = -139.61</h3>

<h3>To find B now </h3><h3>Remember they said B is 4 times the mass of C and C = -139.61</h3>

therefore B = 4 × -139.61

<h3>B = -558.44 kg </h3>

<h3>To check if we are correct, we add the masses of A, B and C to see if it equals their total mass which is 1.95kg</h3>

<h3>Using your calculator: </h3>

= 700 + ( -558.44 ) + ( -139.61 )

= 700 - 558.44 -139.61

= 1.95 kg

Which makes us CORRECT ✅.

<h3>Hope this helps.</h3><h3>Good luck ✅.</h3>

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Answer:

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We are given;

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