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liq [111]
3 years ago
9

An observer (O) is located 400 feet from a building (B). The observer notices a kite (K) flying at a 29° angle of elevation from

his line of sight. How high is the kite flying over the building? You must show all work and calculations to receive full credit. (10 points)
A right triangle is shown with one leg measuring 400 and another leg measuring h with an angle across from it measuring 29 degree

Mathematics
1 answer:
Alex787 [66]3 years ago
8 0

Answer:

Solution given:

angle of elevation [A]=29°

height [p]=?

base[b]=400ft

since

relationship between base and height is given by Tan angle

we have

Tan 29°=opposite/adjacent

Tan29°=perpendicular [P]/base[b]=P/400

P=Tan29*400

P=221.72ft

<u>the</u><u> </u><u>height</u><u> </u><u>of</u><u> </u><u>the kite flying over the </u><u>building</u><u> </u><u>is</u><u> </u><u>2</u><u>2</u><u>1</u><u>.</u><u>7</u><u>2</u><u>f</u><u>t</u>

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