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3 years ago

9

A recipe calls for 2/5 of a pound of chicken for each person. If there are 8 people to be fed how many pounds of chicken are req

uired?

1 answer:

dybincka [34]3 years ago

8 0

Answer:

3 1/5

Step-by-step explanation:

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HELP PLEASE IM BEGGING YOU

andriy [413]

Answer:

75th term in the sequence is 227.

Step-by-step explanation:

75 term of A.P is

a_75= a+ (n-1)d

Given series is 5,8,11,14.

hence a= 5 d= 8-5 = 3 , a_75.

a_75 = 5+(75-1)3

= 5+ (74)3

= 5 +(222)

= 227

6 0

2 years ago

During a scuba dive, Lainey descended to a point 29 feet below the ocean surface. She continued her descent at a rate of 29 feet

Alex73 [517]

Answer:

Her initial position was:

-29ft

Where we use the minus sign because this is below the ocean's surface.

Now we also know that she keeps descending at a rate of -29ft per minute, then if she keeps descending for t minutes, her position will be:

P(x) = -29ft - 29ft/min*t

Now, we also know that she does not want to descend more than 81ft below the ocean's surface, then we have the inequality:

P(x) ≥ -81ft

-29ft - 29ft/min*t ≥ -81ft

Now let's isolate t in one side:

- 29ft/min*t ≥ -81ft + 29ft = -52 ft

- 29ft/min*t ≥-52 ft

t ≤ -52ft/(- 29ft/min) = 1.79 min

Then the maximum amount of time that she can keep descending is 1.79 minutes.

6 0

3 years ago

Help me? idk the answer :P

Alexus [3.1K]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\
\left( 2^8\cdot 3^{-5}\cdot 6^0 \right)^{-2}\left( \cfrac{3^{-2}}{2^3} \right)^4\cdot 2^{28}\impliedby \textit{let's do the first group}
\\\\
-------------------------------\\\\
$

$\bf \left( 2^8\cdot \cfrac{1}{3^5}\cdot 1 \right)^{-2}\implies \left( \cfrac{2^8}{3^5} \right)^{-2}\implies \left( \cfrac{3^5}{2^8} \right)^{2}\implies \cfrac{3^{2\cdot 5}}{2^{2\cdot 8}}\implies \boxed{\cfrac{3^{10}}{2^{16}}}\\\\
-------------------------------\\\\
\textit{now the second group}\qquad \left( \cfrac{3^{-2}}{2^3} \right)^4\implies \left( \cfrac{\frac{1}{3^2}}{2^3} \right)^4\implies \left( \cfrac{1}{2^3\cdot 3^2} \right)^4$

$\bf \cfrac{1^4}{2^{4\cdot 3}\cdot 3^{4\cdot 2}}\implies \boxed{\cfrac{1}{2^{12}\cdot 3^8}}\\\\
-------------------------------\\\\
\textit{so we end up with\qquad }\cfrac{3^{10}}{2^{16}}\cdot \cfrac{1}{2^{12}\cdot 3^8}\cdot 2^{28}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{16}\cdot 2^{12}\cdot 3^8}
\\\\\\
\cfrac{3^{10}\cdot 2^{28}}{2^{16+12}\cdot 3^8}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{28}\cdot 3^8}\implies 3^{10}\cdot 2^{28}\cdot 2^{-28}\cdot 3^{-8}$

$\bf 3^{10-8}\cdot 2^{28-28}\implies 3^2\cdot 1\implies 3^2\implies 9$

7 0

3 years ago

How do you do this equation

RUDIKE [14]

When you solve, a quadratic formula is set up as ax^2+bx+c so in this scenario a is 1, b is -1 and c is -6.
-(-1)+- √- 1^2-4(1)(-1)/2(1) is
1+/-√1+4/2 equals -2 and 3 making the answer c

4 0

3 years ago

Chords and Arcs - Guided Practice

Mariulka [41]

Answer:

Step-by-step explanation:

A) 120 / 2 = 60°

B) 180 - 90 60 = 30°

C) 60° same as arc length GE in part A above

D) 9 units = Rsinθ = 18sin30

3 0

3 years ago